Chapter 13.5, Problem 13.6BFP

Interpretation Introduction

Interpretation:

The mass percent, molarity and mole percent of ${\text{CaBr}}_2$ are to be calculated.

Concept introduction:

Mass percent is defined as the mass of a component divided by the total mass of the mixture, multiplied by 100.

The formula to calculate the mass percent is as follows:

$\text{Mass}\text{percent}=\left(\frac{\text{mass}\text{of}\text{solute}}{\text{mass}\text{of}\text{solution}}\right)100$ (1)

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by $M$ and its unit is $\text{mol/L}$.

The formula to calculate the molarity of the solution is as follows:

$\text{Molarity}=\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{volume }\left(\text{L}\right)\text{of}\text{}\text{solution}}$ (2)

The mole percent is defined as the ratio of the number of moles of solute to the total number of moles in the mixture, multiplied by 100.

The formula to calculate the mole percent is as follows:

$\text{Mole}\text{percent}=\left(\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}+\text{amount}\left(\text{mol}\right)\text{of}\text{solvent}}\right)100$ (3)