Explanation Given The integral: ∫ 0 2 18 x 2 − 24 x + 6 x 3 − 2 x 2 + x + 12 d x . Calculation: Consider, ∫ 0 2 18 x 2 − 24 x + 6 x 3 − 2 x 2 + x + 12 d x = ∫ 0 2 6 ( 3 x 2 − 4 x + 1 ) x 3 − 2 x 2 + x + 12 d x Let, x 3 − 2 x 2 + x + 12 = t Now, take derivative of above equation to get: ( 3 x 2 − 4 x + 1 ) d x = d t When x = 0 , x 3 − 2 x 2 + x + 12 = t t = ( 0 ) 3 − 2 × ( 0 ) 2 + 0 + 12

Mathematics with Applications In the Management, Natural and Social Sciences (11th Edition)

11th Edition

ISBN: 9780321931078

Author: Margaret L. Lial, Thomas W. Hungerford, John P. Holcomb, Bernadette Mullins

Publisher: PEARSON

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Chapter 13.4, Problem 30E

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Chapter 13 Solutions

Mathematics with Applications In the Management, Natural and Social Sciences (11th Edition)

Ch. 13.1 - Checkpoint 1 Find an antiderivative for each of...Ch. 13.1 - Checkpoint 2 Find each of the...Ch. 13.1 - Prob. 3CP Ch. 13.1 - Prob. 4CP Ch. 13.1 - Prob. 5CP Ch. 13.1 - Prob. 6CP Ch. 13.1 - Prob. 7CP Ch. 13.1 - Checkpoint 8 The marginal cost at a level of...Ch. 13.1 - Prob. 9CP Ch. 13.1 - 1. What must be true of F(x) and G(x) if both are...

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