In Exercises 1−6, ( a ) express dw / dt as a function of t , both by using the Chain Rule and by expressing w in terms of t and differentiating directly with respect to t. Then ( b ) evaluate dw / dt at the given value of t . 2. w = x 2 + y 2 , x = cos t + sin t , y = cos t − sin t ; t = 0
In Exercises 1−6, ( a ) express dw / dt as a function of t , both by using the Chain Rule and by expressing w in terms of t and differentiating directly with respect to t. Then ( b ) evaluate dw / dt at the given value of t . 2. w = x 2 + y 2 , x = cos t + sin t , y = cos t − sin t ; t = 0
In Exercises 1−6, (a) express dw/dt as a function of t, both by using the Chain Rule and by expressing w in terms of t and differentiating directly with respect to t. Then (b) evaluate dw/dt at the given value of t.
2.
w
=
x
2
+
y
2
,
x
=
cos
t
+
sin
t
,
y
=
cos
t
−
sin
t
;
t
=
0
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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