Explanation 1) Definition: Assume that an experiment has outcomes numbered 1 to n with probabilities P 1 , P 2 , P 3 , ... P n . Assume that each outcome has a numerical value associated with it and these are labeled V 1 , V 2 , V 3 , ... V n . The expected value of the experiment is ( P 1 ⋅ V 1 ) + ( P 2 ⋅ V 2 ) + ( P 3 ⋅ V 3 ) + ... + ( P n ⋅ V n ) . 2) Calculation: Given, Hydrants opened Days 20 13 30 11 40 15 50 11 60 9 70 1 The total number of days are given by n ( S ) = 13 + 11 + 15 + 11 + 9 + 1 n ( S ) = 60 The probability that number of 13 days with hydrants department opened P ( A ) = n ( A ) n ( S ) P ( A ) = 13 60 with 20 hydrants The probability that number of 11 days with hydrants department opened. P ( B ) = n ( B ) n ( S ) P ( B ) = 11 60 with 30 hydrants The probability that number of 15 days with hydrants department opened

6th Edition

ISBN: 9780134434681

Author: Tom Pirnot

Publisher: PEARSON

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Chapter 13.4, Problem 14E

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The expected value of hydrants department opened per day during the upcoming heat wave.

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Chapter 13.4, Problem 13E

Chapter 13.4, Problem 15E

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Chapter 13 Solutions

Mathematics All Around (6th Edition)

Ch. 13.1 - In Exercises 14 , write each event as a set of...Ch. 13.1 - In Exercises 14 , write each event as a set of...Ch. 13.1 - In Exercises 14 , write each event as a set of...Ch. 13.1 - Prob. 4E Ch. 13.1 - In Exercises 58, use the given spinner to write...Ch. 13.1 - Prob. 6E Ch. 13.1 - In Exercises 58, use the given spinner to write...Ch. 13.1 - In Exercises 58, use the given spinner to write...Ch. 13.1 - We are rolling two four-sided dice having the...Ch. 13.1 - We are rolling two four-sided dice. One die has...

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Chapter 13 Solutions

To find:

The expected value of hydrants department opened per day during the upcoming heat wave.