Explanation Substitute c = − 4 in log e ( x 2 + c ) and obtain y 1 as follows. y 1 = log e ( x 2 + − 4 ) = log e ( x 2 − 4 ) Substitute c = 0 in log e ( x 2 + c ) and obtain y 2 as, y 2 = log e ( x 2 + 0 ) = log e ( x 2 ) Substitute c = 4 in log e ( x 2 + c ) and obtain y 3 as, y 3 = log e ( x 2 + 4 ) = log e ( x 2 + 4 ) Follow the below mentioned steps to obtain the graph of y 1 = log e ( x 2 − 4 ) , y 2 = log e ( x 2 ) and y 3 = log e ( x 2 + 4 ) using TI-83 graphing calculator: Turn on the TI-83 graphing calculator and press [ Y= ] to enter the right hand side of the function as equations

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Author: Washington

Publisher: PEARSON

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Chapter 13.2, Problem 64E

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To sketch: The graph of y=loge(x2+c) with c=−4,0,4 using a graphing calculator on same screen and explain the results.

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Chapter 13.2, Problem 63E

Chapter 13.2, Problem 65E

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Chapter 13 Solutions

Basic Technical Mathematics

Ch. 13.1 - Evaluate for: 1. Ch. 13.1 - Prob. 2PE Ch. 13.1 - Prob. 1E Ch. 13.1 - Prob. 2E Ch. 13.1 - Prob. 3E Ch. 13.1 - Prob. 4E Ch. 13.1 - In Exercises 3–6, use a calculator to evaluate (to...Ch. 13.1 - Prob. 6E Ch. 13.1 - Prob. 7E Ch. 13.1 - In Exercises 7–10, determine if the given...

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The graph of y = log e ( x 2 + c ) with c = − 4 , 0 , 4 using a graphing calculator on same screen and explain the results.

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To sketch: The graph of y=loge(x2+c) with c=−4,0,4 using a graphing calculator on same screen and explain the results.

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Chapter 13 Solutions