To prove: x ( G ) = n yet G does not have K n as sub-graph. Let n ≥ 4 be a natural number. And G be the graph that consist of union of K n − 3 and a 5-cycle C , together with all possible edges between the vertices.

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Answer 1

Question

Chapter 13.2, Problem 13E

To determine

To prove: x(G)=n yet G does not have Kn as sub-graph. Let n≥4 be a natural number. And G be the graph that consist of union of Kn−3 and a 5-cycle C, together with all possible edges between the vertices.

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Answer 2

Question

Chapter 13.2, Problem 13E

To determine

To prove: x(G)=n yet G does not have Kn as sub-graph. Let n≥4 be a natural number. And G be the graph that consist of union of Kn−3 and a 5-cycle C, together with all possible edges between the vertices.

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Answer 3

Question

Chapter 13.2, Problem 13E

To determine

To prove: x(G)=n yet G does not have Kn as sub-graph. Let n≥4 be a natural number. And G be the graph that consist of union of Kn−3 and a 5-cycle C, together with all possible edges between the vertices.

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Answer 4

Question

Chapter 13.2, Problem 13E

To determine

To prove: x(G)=n yet G does not have Kn as sub-graph. Let n≥4 be a natural number. And G be the graph that consist of union of Kn−3 and a 5-cycle C, together with all possible edges between the vertices.

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Answer 5

Chapter 13.2, Problem 13E

To determine

To prove: x(G)=n yet G does not have Kn as sub-graph. Let n≥4 be a natural number. And G be the graph that consist of union of Kn−3 and a 5-cycle C, together with all possible edges between the vertices.

Answer 6

Chapter 13.2, Problem 13E

To determine

To prove: x(G)=n yet G does not have Kn as sub-graph. Let n≥4 be a natural number. And G be the graph that consist of union of Kn−3 and a 5-cycle C, together with all possible edges between the vertices.

Answer 7

Chapter 13.2, Problem 13E

To determine

To prove: x(G)=n yet G does not have Kn as sub-graph. Let n≥4 be a natural number. And G be the graph that consist of union of Kn−3 and a 5-cycle C, together with all possible edges between the vertices.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 13.1 - Prob. 1TFQ Ch. 13.1 - Prob. 2TFQ Ch. 13.1 - Prob. 3TFQ Ch. 13.1 - Prob. 4TFQ Ch. 13.1 - Prob. 5TFQ Ch. 13.1 - Prob. 6TFQ Ch. 13.1 - Prob. 7TFQ Ch. 13.1 - Prob. 8TFQ Ch. 13.1 - Prob. 9TFQ Ch. 13.1 - Prob. 10TFQ

To prove: x ( G ) = n yet G does not have K n as sub-graph. Let n ≥ 4 be a natural number. And G be the graph that consist of union of K n − 3 and a 5-cycle C , together with all possible edges between the vertices.

Solution Summary: The author explains that G does not contain K_n as a sub-graph.

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To prove: x(G)=n yet G does not have Kn as sub-graph. Let n≥4 be a natural number. And G be the graph that consist of union of Kn−3 and a 5-cycle C, together with all possible edges between the vertices.

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Chapter 13 Solutions