Electrical Wiring: Residental - With Plans (Paperback) Package
18th Edition
ISBN: 9781305416376
Author: MULLIN
Publisher: Cengage
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Textbook Question
Chapter 13, Problem 9R
What is the total current consumption of the track lighting and recessed luminaires above the fireplace? Show your calculations.
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Students have asked these similar questions
Can you rewrite the solution because it is
unclear?
AM
(+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts)
=
cos 10000 πt.
8 cos wat + 4 cos wit + 4 cos Wat coswet.
J4000 t
j11000rt
$14+) = 45
jqooort
+4e
+ e
+ e
j 12000rt.
12000 kt
+ e
+e
+e
Le
jsoort
-; goon t
te
+e
Dcw>
= 885(W- 100007) + 8 IS (W-10000) -
USB
Can you rewrite the solution because it is
unclear?
Q2
AM
①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt)
$4+) = 45
=
*cos 10000 πt.
8 cos wat + 4 cosat + 4 cos Wat coswet.
j1000016
+4e
-j10000πt j11000Rt
j gooort -j 9000 πt
+
e
+e
j sooort
te
+e
J11000 t
+ e
te
j 12000rt.
-J12000 kt
+ с
= 8th S(W- 100007) + 8 IS (W-10000)
<&(w) =
USB
-5-5
-4-5-4
b) Pc 2² = 64
PSB =
42
+ 4
2
Pt Pc+ PSB =
y = Pe
c) Puss =
PLSB =
= 32
4² = 8 w
32+ 8 =
× 100% = 140
(1)³×2×2
31
= 20%
x 2 = 3w
302
USB
4.5 5 5.6 6
ms Ac = 4 mi
= 0.5
mz Ac = 4
५
M2
=
=0.5
A. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and
Manchester code.
Data sequence= (00110100)
B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of
50 dB. If the message is a single tone with fm-5 kHz. Determine:
1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio.
2) Minimum required system bandwidth.
Chapter 13 Solutions
Electrical Wiring: Residental - With Plans (Paperback) Package
Ch. 13 - Prob. 1RCh. 13 - Prob. 2RCh. 13 - Prob. 3RCh. 13 - How many wires must be run between an incandescent...Ch. 13 - Complete the wiring diagram for the dimmer and...Ch. 13 - Is it possible to dim standard fluorescent...Ch. 13 - a. How many wires must be run between a...Ch. 13 - Explain why fluorescent lamps having the same...Ch. 13 - What is the total current consumption of the track...Ch. 13 - Prob. 10R
Ch. 13 - Prob. 11RCh. 13 - Electronic dimmers of the type sold for...Ch. 13 - Prob. 13RCh. 13 - A layout of the outlets, switches, dimmers, track...Ch. 13 - Prob. 15RCh. 13 - Prob. 16RCh. 13 - Prob. 17RCh. 13 - Prob. 18RCh. 13 - May a standard electronic dimmer be used to...Ch. 13 - Prob. 20RCh. 13 - Why should the power be turned off when hooking up...
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- Using the 802.11a specifications given below, in Matlab (or similar tool) create the time domain signal for one OFDM symbol using QPSK modulation. See attached plot for the QPSK constellation. Your results should include the power measure in the time and frequency domain and comment on those results. BW 802.11a OFDM PHY Parameters 20 MHZ OBW Subcarrer Spacing Information Rate Modulation Coding Rate Total Subcarriers Data Subcarriers Pilot Subcarriers DC Subcarrier 16.6 MHZ 312.5 Khz (20MHz/64 Pt FFT) 6/9/12/18/24/36/48/54 Mbits/s BPSK, QPSK, 16QAM, 64QAM 1/2, 2/3, 3/4 52 (Freq Index -26 to +26) 48 4 (-21, -7, +7, +21) *Always BPSK Null (0 subcarrier) 52 subarriers -7 (48 Data, 4 Pilot (BPSK), 1 Null) -26 -21 0 7 21 +26 14 One Subcarrier 1 OFDM symbol 1 OFDM Burst -OBW 16.6 MHz BW 20 MHZ 1 constellation point = 52 subcarriers = one or more OFDM symbols 802.11a OFDM Physical Parameters Show signal at this point x bits do Serial Data d₁ S₁ Serial-to- Input Signal Parallel Converter IFFT…arrow_forwardFind Vb and Va using Mesh analysisarrow_forward1. The communication channel bandwidth is 25 MHz centered at 1GHz and has a noise power spectral density of 10^-9 W/Hz. The channel loss between the transmitter and receiver is 25dB. The application requires a bit rate of 200Mbps and BER of less than 10^-4. Excluding Mary FSK, Determine the minimum transmit power required.arrow_forward
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