Chapter 13, Problem 98IAE

Interpretation Introduction

(a)

Interpretation:

The reason; for the slope of the standard molar entropy of the solid chloroform is greater than the slope for the standard molar entropy of the liquid chloroform, which is greater than the slope for the standard molar entropy of the gas chloroform, should be explained.

Concept introduction:

Entropy change for heating or cooling at a constant pressure in non-transitional period ? S,

$\Delta S={\text{C}}_{\text{p}}\ln \left(\frac{T_f}{T_i}\right)$

Where,

$\begin{array}{l}\Delta S=\text{Entropy change}\\ {\text{C}}_{\text{p}}=\text{Constant}\\ T_f=\text{Final temprature}\\ T_i=\text{Initial temprature}\end{array}$

Interpretation Introduction

(b)

Interpretation:

The reason should be explained for the change in standard molar entropy from solid to liquid is smaller than that for the liquid to gas for chloroform.

Concept introduction:

For aphase transitional period,

${\Delta }_t{}_{ra}S=\frac{{\Delta }_{tra}H}{T}$

Where,

$\begin{array}{l}{\Delta }_t{}_{ra}S=\text{Entropy change}\\ {\Delta }_{tra}H=\text{Enthalpy change}\\ T=\text{ Temprature}\end{array}$