Chapter 13, Problem 91QAP

Interpretation Introduction

Interpretation:

The volume of water vapour at 350 ${}^{\circ }\text{C}$ and 1.04 atm should be calculated.

Concept Introduction:

According to ideal gas equation:

$\text{P}\text{V}=\text{n}\text{R}\text{T}$

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.

The value of Universal gas constant can be taken as $0.082{\text{ L atm K}}^{-1}{\text{ mol}}^{-1}$.

Mass of gas can be calculated from number of moles and molar mass as follows:

$\text{m}=\text{n}\times \text{M}$

Here, n is number of moles, m is mass and M is molar mass.