A rectangular copper loop of mass 100 g and resistance 0.2 Ω is in a region of uniform magnetic field that is perpendicular to the area enclosed by the ring and horizontal to Earth's surface (see below). The loop is let go from rest what it is at the edge of the nonzero magnetic field region. (a) Find an expression for the speed when the loop just exits the region of uniform magnetic field. (b) If it was let go at t = 0, what is the tune when it exits the region of magnetic field for the following values, a = 25 c m , b = 50 c m , B = 3 T , g = 9.8 m / s 2 ?Assumethat the magnetic field of the induced current is negligible compared to 3 T.
A rectangular copper loop of mass 100 g and resistance 0.2 Ω is in a region of uniform magnetic field that is perpendicular to the area enclosed by the ring and horizontal to Earth's surface (see below). The loop is let go from rest what it is at the edge of the nonzero magnetic field region. (a) Find an expression for the speed when the loop just exits the region of uniform magnetic field. (b) If it was let go at t = 0, what is the tune when it exits the region of magnetic field for the following values, a = 25 c m , b = 50 c m , B = 3 T , g = 9.8 m / s 2 ?Assumethat the magnetic field of the induced current is negligible compared to 3 T.
A rectangular copper loop of mass 100 g and resistance
0.2
Ω
is in a region of uniform magnetic field that is perpendicular to the area enclosed by the ring and horizontal to Earth's surface (see below). The loop is let go from rest what it is at the edge of the nonzero magnetic field region. (a) Find an expression for the speed when the loop just exits the region of uniform magnetic field. (b) If it was let go at t = 0, what is the tune when it exits the region of magnetic field for the following values,
a
=
25
c
m
,
b
=
50
c
m
,
B
=
3
T
,
g
=
9.8
m
/
s
2
?Assumethat the magnetic field of the induced current is negligible compared to 3 T.
Show that the units 1 v2/Q = 1 W, as implied by the equation P = V²/R.
Starting with the equation P = V²/R, we can get an expression for a watt in terms of voltage and resistance. The units for voltage, V, are equivalent to [?
v2
v2
A, are equivalent to J/C ✓ X . Therefore, 1
= 1
= 1 A V1 J/s
Ω
V-A X
= 1 W.
. The units for resistance, Q, are equivalent to ?
The units for current,
Please solve and answer the question correctly please. Thank you!!
Please solve and answer the question correctly please. Thank you!!
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
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What is Electromagnetic Induction? | Faraday's Laws and Lenz Law | iKen | iKen Edu | iKen App; Author: Iken Edu;https://www.youtube.com/watch?v=3HyORmBip-w;License: Standard YouTube License, CC-BY