
Discrete Mathematics: Introduction to Mathematical Reasoning
1st Edition
ISBN: 9780495826170
Author: Susanna S. Epp
Publisher: Cengage Learning
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Chapter 1.3, Problem 8ES
a.
To determine
To calculate: The solution of the arrow diagram for
b.
To determine
To calculate: The solution of the relations
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Find a basis and dimension for the null space of the following matrix:
3 -2 0 7
-2
1-1 1
5 3 19-2
8
06
1
-2 -4
-5-6
-9
4-6
11
6
Find a basis and dimension for the column space of the same matrix (above).
3. (i) Below is the R code for performing a X2 test on a 2×3 matrix of categorical
variables called TestMatrix:
chisq.test(Test Matrix)
(a) Assuming we have a significant result for this procedure, provide the R
code (including any required packages) for an appropriate post hoc test.
(b) If we were to apply this technique to a 2 × 2 case, how would we adapt
the code in order to perform the correct test?
(ii) What procedure can we use if we want to test for association when we
have ordinal variables? What code do we use in R to do this? What package
does this command belong to?
(iii) The following code contains the initial steps for a scenario where we are
looking to investigate the relationship between age and whether someone owns
a car by using frequencies. There are two issues with the code - please state
these.
Row3<-c(75,15)
Row4<-c(50,-10)
MortgageMatrix<-matrix(c(Row1, Row4), byrow=T, nrow=2,
MortgageMatrix
dimnames=list(c("Yes", "No"), c("40 or older","<40")))…
Describe the situation in which Fisher’s exact test would be used?(ii) When do we use Yates’ continuity correction (with respect to contingencytables)?[2 Marks] 2. Investigate, checking the relevant assumptions, whether there is an associationbetween age group and home ownership based on the sample dataset for atown below:Home Owner: Yes NoUnder 40 39 12140 and over 181 59Calculate and evaluate the effect size.
Chapter 1 Solutions
Discrete Mathematics: Introduction to Mathematical Reasoning
Ch. 1.1 - Prob. 1ESCh. 1.1 - Prob. 2ESCh. 1.1 - Prob. 3ESCh. 1.1 - Prob. 4ESCh. 1.1 - Prob. 5ESCh. 1.1 - Prob. 6ESCh. 1.1 - Prob. 7ESCh. 1.1 - Prob. 8ESCh. 1.1 - Prob. 9ESCh. 1.1 - Prob. 10ES
Ch. 1.1 - Prob. 11ESCh. 1.1 - Prob. 12ESCh. 1.1 - Prob. 13ESCh. 1.2 - Prob. 1ESCh. 1.2 - Prob. 2ESCh. 1.2 - Prob. 3ESCh. 1.2 - Prob. 4ESCh. 1.2 - Prob. 5ESCh. 1.2 - Prob. 6ESCh. 1.2 - Prob. 7ESCh. 1.2 - Prob. 8ESCh. 1.2 - Prob. 9ESCh. 1.2 - Prob. 10ESCh. 1.2 - Prob. 11ESCh. 1.2 - Prob. 12ESCh. 1.3 - Prob. 1ESCh. 1.3 - Prob. 2ESCh. 1.3 - Prob. 3ESCh. 1.3 - Prob. 4ESCh. 1.3 - Prob. 5ESCh. 1.3 - Prob. 6ESCh. 1.3 - Prob. 7ESCh. 1.3 - Prob. 8ESCh. 1.3 - Prob. 9ESCh. 1.3 - Prob. 10ESCh. 1.3 - Prob. 11ESCh. 1.3 - Prob. 12ESCh. 1.3 - Prob. 13ESCh. 1.3 - Prob. 14ESCh. 1.3 - Prob. 15ESCh. 1.3 - Prob. 16ESCh. 1.3 - Prob. 17ESCh. 1.3 - Prob. 18ESCh. 1.3 - Prob. 19ESCh. 1.3 - Prob. 20ES
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- solve these pleasearrow_forwardA factorization A = PDP 1 is not unique. For A= 7 2 -4 1 1 1 5 0 2 1 one factorization is P = D= and P-1 30 = Use this information with D₁ = to find a matrix P₁ such that - -1 -2 0 3 1 - - 1 05 A-P,D,P P1 (Type an integer or simplified fraction for each matrix element.)arrow_forwardMatrix A is factored in the form PDP 1. Use the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace. 30 -1 - 1 0 -1 400 0 0 1 A= 3 4 3 0 1 3 040 3 1 3 0 0 4 1 0 0 003 -1 0 -1 Select the correct choice below and fill in the answer boxes to complete your choice. (Use a comma to separate vectors as needed.) A basis for the corresponding eigenspace is { A. There is one distinct eigenvalue, λ = B. In ascending order, the two distinct eigenvalues are λ₁ ... = and 2 = Bases for the corresponding eigenspaces are { and ( ), respectively. C. In ascending order, the three distinct eigenvalues are λ₁ = = 12/2 = and 3 = Bases for the corresponding eigenspaces are {}, }, and { respectively.arrow_forward
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