Discrete Mathematics: Introduction to Mathematical Reasoning
Discrete Mathematics: Introduction to Mathematical Reasoning
1st Edition
ISBN: 9780495826170
Author: Susanna S. Epp
Publisher: Cengage Learning
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Logic is the analysis of general patterns of thoughts without regard to any specific sense of context.
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Chapter 1.1, Problem 2ES

a.

To determine

To calculate: The solutions of the blank using the variable.

b.

To determine

To calculate: The solutions of the blank using the variable.

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Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a. f(x) = (x + 4x4) 5, a = -1 lim f(x) X--1 = lim x+4x X--1 lim X-1 4 x+4x 5 ))" 5 )) by the power law by the sum law lim (x) + lim X--1 4 4x X-1 -(0,00+( Find f(-1). f(-1)=243 lim (x) + -1 +4 35 4 ([ ) lim (x4) 5 x-1 Thus, by the definition of continuity, f is continuous at a = -1. by the multiple constant law by the direct substitution property
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Chapter 1 Solutions

Discrete Mathematics: Introduction to Mathematical Reasoning

Ch. 1.1 - Prob. 1ESCh. 1.1 - Prob. 2ESCh. 1.1 - Prob. 3ESCh. 1.1 - Prob. 4ESCh. 1.1 - Prob. 5ESCh. 1.1 - Prob. 6ESCh. 1.1 - Prob. 7ESCh. 1.1 - Prob. 8ESCh. 1.1 - Prob. 9ESCh. 1.1 - Prob. 10ES
Ch. 1.1 - Prob. 11ESCh. 1.1 - Prob. 12ESCh. 1.1 - Prob. 13ESCh. 1.2 - Prob. 1ESCh. 1.2 - Prob. 2ESCh. 1.2 - Prob. 3ESCh. 1.2 - Prob. 4ESCh. 1.2 - Prob. 5ESCh. 1.2 - Prob. 6ESCh. 1.2 - Prob. 7ESCh. 1.2 - Prob. 8ESCh. 1.2 - Prob. 9ESCh. 1.2 - Prob. 10ESCh. 1.2 - Prob. 11ESCh. 1.2 - Prob. 12ESCh. 1.3 - Prob. 1ESCh. 1.3 - Prob. 2ESCh. 1.3 - Prob. 3ESCh. 1.3 - Prob. 4ESCh. 1.3 - Prob. 5ESCh. 1.3 - Prob. 6ESCh. 1.3 - Prob. 7ESCh. 1.3 - Prob. 8ESCh. 1.3 - Prob. 9ESCh. 1.3 - Prob. 10ESCh. 1.3 - Prob. 11ESCh. 1.3 - Prob. 12ESCh. 1.3 - Prob. 13ESCh. 1.3 - Prob. 14ESCh. 1.3 - Prob. 15ESCh. 1.3 - Prob. 16ESCh. 1.3 - Prob. 17ESCh. 1.3 - Prob. 18ESCh. 1.3 - Prob. 19ESCh. 1.3 - Prob. 20ES
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