Explanation Given data: The depth is 11 km. Formula used: Write the expression for pressure of a liquid ( p ) . p = p 0 + ρ g d (1) Here, p 0 is pressure at the surface, ρ is density of liquid, g is gravity, and d is depth of liquid. Explanation: Refer to Table 13.1 in the textbook for the densities of fluids at 1 atm pressure. From table 13.1, the density of sea water is 1030 kg m 3 at pressure 1 atm. Consider the value of gravity as 9.80 m s 2 . Substitute 1 atm for p 0 , 1030 kg m 3 for ρ , 9.80 m s 2 for g , and 11 km for d in equation (1), p = 1 atm + ( 1030 kg m 3 ) ( 9.80 m s 2 ) ( 11 km ) = 1 atm + ( 1030 kg m 3 ) ( 9

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Chapter 13, Problem 7P

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The pressure in atmosphere at 11 km below sea level.

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The pressure in atmosphere at 11 km below sea level.

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The pressure in atmosphere at 11 km below sea level.

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Chapter 13 Solutions