Explanation Given data: The volume of pool is 6000 L, diameter of hose 2.5 cm , and speed is 2.1 m s . Formula used: Write the expression for volume of tube ( V ) . V = A v Δ t (1) Here, A is cross-section area of pipe, v is speed, and Δ t is interval of time. Write the expression for area of pipe ( A ) . A = π r 2 Here, r is radius. Explanation: Find the radius of pipe ( r ) . r = 2.5 cm 2 = 1.25 cm = 0 .0125 m { ∵ 1 cm = 0.01 m } Substitute π r 2 for A in equation (1), V = ( π r 2 ) v Δ t Re-arrange the equation. Δ t = V π r 2 v Substitute 6000 L for V , 0 .0125 m for r , and 2

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ISBN: 9780134700427

Author: Knight

Publisher: PEARSON

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Variation of pressure

From the equation of pressure, pressure is directly proportional to the applied force.

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Chapter 13, Problem 34P

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The time taken to empty the pool.

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Chapter 13, Problem 33P

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