Use the approach of Exercise 77 to show that d d x f ( x ) = d d x ( f ( x ) + c ) For any costant c .[Hint: Compare the tangent lines to the graph of f ( x ) and f ( x ) + c ] Draw two graphs of your choice that represent a function y = f ( x ) and its vertical shift y = f ( x ) + 3 Pick a value of x and consider the points ( x , f ( x ) ) and ( x , f ( x ) + 3 ) . Draw the tangent lines to the curves at these points and describe what you observe about the tangent lines. Based on your observation in part (b), explain why d d x f ( x ) = d d x ( f ( x ) + 3 )
Use the approach of Exercise 77 to show that d d x f ( x ) = d d x ( f ( x ) + c ) For any costant c .[Hint: Compare the tangent lines to the graph of f ( x ) and f ( x ) + c ] Draw two graphs of your choice that represent a function y = f ( x ) and its vertical shift y = f ( x ) + 3 Pick a value of x and consider the points ( x , f ( x ) ) and ( x , f ( x ) + 3 ) . Draw the tangent lines to the curves at these points and describe what you observe about the tangent lines. Based on your observation in part (b), explain why d d x f ( x ) = d d x ( f ( x ) + 3 )
Solution Summary: The author analyzes the function representing y=f(x) and its vertical shift. The tangent lines for the curves are parallel and the slopes of the parallel lines are equal
For any costant
c
.[Hint: Compare the tangent lines to the graph of
f
(
x
)
and
f
(
x
)
+
c
]
Draw two graphs of your choice that represent a function
y
=
f
(
x
)
and its vertical shift
y
=
f
(
x
)
+
3
Pick a value of
x
and consider the points
(
x
,
f
(
x
)
)
and
(
x
,
f
(
x
)
+
3
)
. Draw the tangent lines to the curves at these points and describe what you observe about the tangent lines.
Based on your observation in part (b), explain why
d
d
x
f
(
x
)
=
d
d
x
(
f
(
x
)
+
3
)
According to Newton's law of universal gravitation, the force F between two bodies of constant mass
GmM
m and M is given by the formula F =
, where G is the gravitational constant and d is the
d²
distance between the bodies.
a. Suppose that G, m, and M are constants. Find the rate of change of force F with respect to
distance d.
F' (d)
2GmM
b. Find the rate of change of force F with gravitational constant G = 6.67 × 10-¹¹ Nm²/kg², on
two bodies 5 meters apart, each with a mass of 250 kilograms. Answer in scientific notation,
rounding to 2 decimal places.
-6.67x10
N/m syntax incomplete.
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