Explanation Given information : The equation of line passing through point ( h , k ) , having slope m is given by y − k = m ( x − h ) . Formula used : Slope of a line is the tangent of angle that line makes with x-axis. Proof: The line passes through point P ( h , k ) has the slope m. Let the line segment AB makes angle θ with x-axis such that A( x , y ) is general point on it and line meet x-axis at point B as shown in figure. Let AL and PM are the perpendicular from points A and P on x-axis respectively. We draw a perpendicular AN, frompoint A on the line PM. From the figure; we see ∠ ABM= θ ⇒ ∠ PAN= θ , and I n Δ PAN , we have tan θ= PN AN

Student's Solution and Survival Manual for Calculus

7th Edition

ISBN: 9781524934040

Author: STRAUSS MONTY J, TODA MAGDALENA DANIELE, SMITH KARL J

Publisher: Kendall Hunt Publishing

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Chapter 1.3, Problem 55PS

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Toshow:The given equation is the equation of a line with slope m passing through point (h,k) .

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Chapter 1.3, Problem 54PS

Chapter 1.3, Problem 56PS

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Chapter 1 Solutions

Student's Solution and Survival Manual for Calculus

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Toshow: The given equation is the equation of a line with slope m passing through point ( h , k ) .

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Toshow:The given equation is the equation of a line with slope m passing through point (h,k) .

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Chapter 1 Solutions