Physics of Everyday Phenomena
Physics of Everyday Phenomena
9th Edition
ISBN: 9781260048469
Author: Griffith
Publisher: MCG
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Chapter 13, Problem 4SP

In the combination of 12 Ω resistors shown in the diagram, there are two different parallel combinations that, in turn, are in series with the middle resistor.

a.    What is the resistance of each of the two parallel combinations?

b.    What is the total equivalent resistance between points A and B?

c.    If there is a voltage difference of 18 V between points A and B, what is the current flowing through the entire combination?

d.    What is the current flowing through each of the resistors in the three-resistor parallel combination?

Chapter 13, Problem 4SP, In the combination of 12  resistors shown in the diagram, there are two different parallel

(a)

Expert Solution
Check Mark
To determine

The equivalent resistance of the two parallel segments.

Answer to Problem 4SP

The current through the circuit is 0.057A.

Explanation of Solution

Given info: The given circuit is shown below.

Physics of Everyday Phenomena, Chapter 13, Problem 4SP , additional homework tip  1

Write the formula for the resultant resistance of two equal resistors connected in parallel.

R2=R2

Here,

R2 is the equivalent resistance of the two equal parallel resistors

R is the resistance of each resistor

Substitute 12Ω for R to determine the equivalent resistance of the parallel connection of two 12Ω.

R2=12Ω3=6Ω

Write the formula for the resultant resistance of three equal resistors connected in parallel.

R3=R3

Here,

R3 is the equivalent resistance of the three equal parallel resistors

R is the resistance of each resistor

Substitute 12Ω for R to determine the equivalent resistance of the parallel cpnnection of three 12Ω.

R3=12Ω3=4Ω

Conclusion:

The equivalent resistance of the two parallel connections in the arrangement is 6Ω and 4Ω.

(b)

Expert Solution
Check Mark
To determine

The equivalent resistance between point A to B.

Answer to Problem 4SP

The overall resistance between points A and B is 22Ω.

Explanation of Solution

Given info: The given circuit is shown below.

Physics of Everyday Phenomena, Chapter 13, Problem 4SP , additional homework tip  2

In this arrangement the two parallel segments and one 12Ω are in series. The equivalent resistance will be the sum of the resistances of all the three segments from point A and B.

Write the formula for the equivalent resistance between point A and B.

R=R1+R2+R3

Here,

R is the equivalent resistance between point A and B

R1 is the resistance of the first segment

R2 is the resistance of the second segment

R3 is the resistance of the third segment

Substitute 6Ω for 6Ω , 12Ω for R2, 4Ω for R3 to determine R.

R=6Ω+12Ω+4Ω=22Ω

Conclusion:

The overall resistance between points A and B is 22Ω.

(c)

Expert Solution
Check Mark
To determine

The current flowing through the circuit.

Answer to Problem 4SP

The current in the circuit is 0.818A.

Explanation of Solution

Given info: The voltage difference between point A and B is 18V. The given circuit is shown below.

Physics of Everyday Phenomena, Chapter 13, Problem 4SP , additional homework tip  3

Write the formula for current.

I=VR

Here,

R is the equivalent resistance between point A and B

I is the current

V is the voltage difference

From section (b) the overall resistance between points A and B is 22Ω.

Substitute 22Ω for R, 18V for V to determine I.

I=18V22Ω=0.818A

Conclusion:

The current in the circuit is 0.818A.

(d)

Expert Solution
Check Mark
To determine

The current flowing through the individual resistors in the three-resistor parallel combination.

Answer to Problem 4SP

The current flowing through the individual resistors in the three-resistor parallel combination is 0.273A.

Explanation of Solution

Given info: The given circuit is shown below.

Physics of Everyday Phenomena, Chapter 13, Problem 4SP , additional homework tip  4

The current through all the segments will be same. From section (c) the current in the circuit is 0.818A. So the total current in the three-register parallel segment is 0.818A.

The current through each segment of a parallel connection of resistors depends on the resistance of each resistor. Since the resistance of the three resistors is same, equal current will pass through the individual resistor which is one third of the total current.

Write the formula for the current through each of the resistor in the three-resistor parallel segment.

Ii=I3

Here,

Ii is the current through each resistor

I is the total current

Substitute 0.818A for Ii to determine I.

Ii=0.818A3=0.273A

Conclusion:

The current flowing through the individual resistors in the three-resistor parallel combination is 0.273A.

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Chapter 13 Solutions

Physics of Everyday Phenomena

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