Product of the given reaction has to be drawn. Concept Introduction: Lithium diisopropylamide is a strong base. Therefore, it can abstract a proton from α carbon atom of a ketone . Enolate ion thus formed can be a thermodynamic enolate or a kinetic enolate ion. Thermodynamic enolate ion is formed at temperature 0 ° C . Kinetic enolate ion is formed at temperature − 7 8 ° C .

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Chapter 13, Problem 43P

Interpretation Introduction

Interpretation:

Product of the given reaction has to be drawn.

Concept Introduction:

Lithium diisopropylamide is a strong base. Therefore, it can abstract a proton from α carbon atom of a ketone. Enolate ion thus formed can be a thermodynamic enolate or a kinetic enolate ion. Thermodynamic enolate ion is formed at temperature 0 °C. Kinetic enolate ion is formed at temperature −78 °C.

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Answer 2

Question

Chapter 13, Problem 43P

Interpretation Introduction

Interpretation:

Product of the given reaction has to be drawn.

Concept Introduction:

Lithium diisopropylamide is a strong base. Therefore, it can abstract a proton from α carbon atom of a ketone. Enolate ion thus formed can be a thermodynamic enolate or a kinetic enolate ion. Thermodynamic enolate ion is formed at temperature 0 °C. Kinetic enolate ion is formed at temperature −78 °C.

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Answer 3

Question

Chapter 13, Problem 43P

Interpretation Introduction

Interpretation:

Product of the given reaction has to be drawn.

Concept Introduction:

Lithium diisopropylamide is a strong base. Therefore, it can abstract a proton from α carbon atom of a ketone. Enolate ion thus formed can be a thermodynamic enolate or a kinetic enolate ion. Thermodynamic enolate ion is formed at temperature 0 °C. Kinetic enolate ion is formed at temperature −78 °C.

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Answer 4

Question

Chapter 13, Problem 43P

Interpretation Introduction

Interpretation:

Product of the given reaction has to be drawn.

Concept Introduction:

Lithium diisopropylamide is a strong base. Therefore, it can abstract a proton from α carbon atom of a ketone. Enolate ion thus formed can be a thermodynamic enolate or a kinetic enolate ion. Thermodynamic enolate ion is formed at temperature 0 °C. Kinetic enolate ion is formed at temperature −78 °C.

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Answer 5

Chapter 13, Problem 43P

Interpretation Introduction

Interpretation:

Product of the given reaction has to be drawn.

Concept Introduction:

Lithium diisopropylamide is a strong base. Therefore, it can abstract a proton from α carbon atom of a ketone. Enolate ion thus formed can be a thermodynamic enolate or a kinetic enolate ion. Thermodynamic enolate ion is formed at temperature 0 °C. Kinetic enolate ion is formed at temperature −78 °C.

Answer 6

Chapter 13, Problem 43P

Interpretation Introduction

Interpretation:

Product of the given reaction has to be drawn.

Concept Introduction:

Lithium diisopropylamide is a strong base. Therefore, it can abstract a proton from α carbon atom of a ketone. Enolate ion thus formed can be a thermodynamic enolate or a kinetic enolate ion. Thermodynamic enolate ion is formed at temperature 0 °C. Kinetic enolate ion is formed at temperature −78 °C.

Answer 7

Chapter 13, Problem 43P

Interpretation Introduction

Interpretation:

Product of the given reaction has to be drawn.

Concept Introduction:

Lithium diisopropylamide is a strong base. Therefore, it can abstract a proton from α carbon atom of a ketone. Enolate ion thus formed can be a thermodynamic enolate or a kinetic enolate ion. Thermodynamic enolate ion is formed at temperature 0 °C. Kinetic enolate ion is formed at temperature −78 °C.

Answer 8

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Answer 11

Ch. 13.1 - Identify the most acidic hydrogen in each...Ch. 13.1 - Prob. 2P Ch. 13.1 - Prob. 3P Ch. 13.1 - Prob. 4P Ch. 13.1 - Explain why HO cannot remove a proton from the...Ch. 13.2 - Prob. 6P Ch. 13.2 - Prob. 7P Ch. 13.3 - Prob. 8P Ch. 13.3 - Prob. 9P Ch. 13.3 - Prob. 10P

Solution Summary: The author explains that Lithium diisopropylamide is a strong base, which abstracts proton from carbon atoms. Kinetic enolate ion is irreversible, while thermodynamic

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