Chapter 13, Problem 37RE

To determine

To find: The probability that the bill is $1 bill.

Answer to Problem 37RE

Therequired probability is $\frac{4}{9}$ .

Explanation of Solution

Given:

The bill is split in four $1, three $5 and two $10 bills.

Calculation:

The number of ways in which the 5 balls can be drawn is $p\left(10,5\right)$ .

Consider the number of elements in the sample space is,

  $n\left(s\right)=n\left(A\right)+n\left(B\right)+n\left(C\right)$

Then,

  $\begin{array}{c}n\left(s\right)=4+3+2\\ =9\end{array}$

Consider the probability of the event is,

  $P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}$

Then, the probability that $1 bill is picked is,

  $P\left(E\right)=\frac{4}{9}$