In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

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Answer 1

Textbook Question

Chapter 13, Problem 34SE

In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

Chapter 13, Problem 34SE, In a completely randomized experimental design, three brands of paper towels were tested for their

Expert Solution & Answer

To determine

Check whether there is a significant difference in the ability of the brands to absorb water at α=0.05 level of significance.

Answer to Problem 34SE

Yes, there is a significant difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represent the absorbency rate for the three brands.

Assume that μ1, μ2, and μ3 denote the population means of three brands x, y, and z, respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha:At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way ANOVA:

Software procedure:

Step-by-step procedure to obtain one-way ANOVA using EXCEL:

Open the EXCEL.
Enter x, y, and z in different columns.
On Data tab in analysis group, click Data Analysis.
Select Anova: Single Factor.
Click OK.
Click in the Input Range box, select x, y, and z.
Click OK.

The output obtained using EXCEL software is shown below:

Modern Business Statistics with Microsoft Office Excel (with XLSTAT Education Edition Printed Access Card) (MindTap Course List), Chapter 13, Problem 34SE

From the output, it is observed that the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If thep-value≤α, reject the null hypothesis H0.

If thep-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference in the ability of the brands to absorb water.

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Find the error: daily_sales = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0] days_of_week = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'] for i in range(7): daily_sales[i] = float(input('Enter the sales for ' \ + day_of_week[i] + ': ')

Find the error: daily_sales = [0.0, 0,0, 0.0, 0.0, 0.0, 0.0, 0.0] days_of_week = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'] for i in range(7): daily_sales[i] = float(input('Enter the sales for ' \ + days_of_week[i] + ': ')

Find the error: daily_sales = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0] days_of_week = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'] for i in range(6): daily_sales[i] = float(input('Enter the sales for ' \ + days_of_week[i] + ': '))

Answer 2

Textbook Question

Chapter 13, Problem 34SE

In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

Chapter 13, Problem 34SE, In a completely randomized experimental design, three brands of paper towels were tested for their

Expert Solution & Answer

To determine

Check whether there is a significant difference in the ability of the brands to absorb water at α=0.05 level of significance.

Answer to Problem 34SE

Yes, there is a significant difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represent the absorbency rate for the three brands.

Assume that μ1, μ2, and μ3 denote the population means of three brands x, y, and z, respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha:At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way ANOVA:

Software procedure:

Step-by-step procedure to obtain one-way ANOVA using EXCEL:

Open the EXCEL.
Enter x, y, and z in different columns.
On Data tab in analysis group, click Data Analysis.
Select Anova: Single Factor.
Click OK.
Click in the Input Range box, select x, y, and z.
Click OK.

The output obtained using EXCEL software is shown below:

Modern Business Statistics with Microsoft Office Excel (with XLSTAT Education Edition Printed Access Card) (MindTap Course List), Chapter 13, Problem 34SE

From the output, it is observed that the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If thep-value≤α, reject the null hypothesis H0.

If thep-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference in the ability of the brands to absorb water.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 13, Problem 34SE

In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

Chapter 13, Problem 34SE, In a completely randomized experimental design, three brands of paper towels were tested for their

Expert Solution & Answer

To determine

Check whether there is a significant difference in the ability of the brands to absorb water at α=0.05 level of significance.

Answer to Problem 34SE

Yes, there is a significant difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represent the absorbency rate for the three brands.

Assume that μ1, μ2, and μ3 denote the population means of three brands x, y, and z, respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha:At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way ANOVA:

Software procedure:

Step-by-step procedure to obtain one-way ANOVA using EXCEL:

Open the EXCEL.
Enter x, y, and z in different columns.
On Data tab in analysis group, click Data Analysis.
Select Anova: Single Factor.
Click OK.
Click in the Input Range box, select x, y, and z.
Click OK.

The output obtained using EXCEL software is shown below:

Modern Business Statistics with Microsoft Office Excel (with XLSTAT Education Edition Printed Access Card) (MindTap Course List), Chapter 13, Problem 34SE

From the output, it is observed that the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If thep-value≤α, reject the null hypothesis H0.

If thep-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference in the ability of the brands to absorb water.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 13, Problem 34SE

In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

Chapter 13, Problem 34SE, In a completely randomized experimental design, three brands of paper towels were tested for their

Expert Solution & Answer

To determine

Check whether there is a significant difference in the ability of the brands to absorb water at α=0.05 level of significance.

Answer to Problem 34SE

Yes, there is a significant difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represent the absorbency rate for the three brands.

Assume that μ1, μ2, and μ3 denote the population means of three brands x, y, and z, respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha:At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way ANOVA:

Software procedure:

Step-by-step procedure to obtain one-way ANOVA using EXCEL:

Open the EXCEL.
Enter x, y, and z in different columns.
On Data tab in analysis group, click Data Analysis.
Select Anova: Single Factor.
Click OK.
Click in the Input Range box, select x, y, and z.
Click OK.

The output obtained using EXCEL software is shown below:

Modern Business Statistics with Microsoft Office Excel (with XLSTAT Education Edition Printed Access Card) (MindTap Course List), Chapter 13, Problem 34SE

From the output, it is observed that the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If thep-value≤α, reject the null hypothesis H0.

If thep-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference in the ability of the brands to absorb water.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

Check whether there is a significant difference in the ability of the brands to absorb water at α=0.05 level of significance.

Answer to Problem 34SE

Yes, there is a significant difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represent the absorbency rate for the three brands.

Assume that μ1, μ2, and μ3 denote the population means of three brands x, y, and z, respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha:At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way ANOVA:

Software procedure:

Step-by-step procedure to obtain one-way ANOVA using EXCEL:

Open the EXCEL.
Enter x, y, and z in different columns.
On Data tab in analysis group, click Data Analysis.
Select Anova: Single Factor.
Click OK.
Click in the Input Range box, select x, y, and z.
Click OK.

The output obtained using EXCEL software is shown below:

Modern Business Statistics with Microsoft Office Excel (with XLSTAT Education Edition Printed Access Card) (MindTap Course List), Chapter 13, Problem 34SE

From the output, it is observed that the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If thep-value≤α, reject the null hypothesis H0.

If thep-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference in the ability of the brands to absorb water.

Answer 8

Expert Solution & Answer

To determine

Check whether there is a significant difference in the ability of the brands to absorb water at α=0.05 level of significance.

Answer to Problem 34SE

Yes, there is a significant difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represent the absorbency rate for the three brands.

Assume that μ1, μ2, and μ3 denote the population means of three brands x, y, and z, respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha:At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way ANOVA:

Software procedure:

Step-by-step procedure to obtain one-way ANOVA using EXCEL:

Open the EXCEL.
Enter x, y, and z in different columns.
On Data tab in analysis group, click Data Analysis.
Select Anova: Single Factor.
Click OK.
Click in the Input Range box, select x, y, and z.
Click OK.

The output obtained using EXCEL software is shown below:

Modern Business Statistics with Microsoft Office Excel (with XLSTAT Education Edition Printed Access Card) (MindTap Course List), Chapter 13, Problem 34SE

From the output, it is observed that the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If thep-value≤α, reject the null hypothesis H0.

If thep-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference in the ability of the brands to absorb water.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

Check whether there is a significant difference in the ability of the brands to absorb water at α=0.05 level of significance.

Answer 12

Answer to Problem 34SE

Yes, there is a significant difference in the ability of the brands to absorb water.

Answer 13

Explanation of Solution

Calculation:

The data represent the absorbency rate for the three brands.

Assume that μ1, μ2, and μ3 denote the population means of three brands x, y, and z, respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha:At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way ANOVA:

Software procedure:

Step-by-step procedure to obtain one-way ANOVA using EXCEL:

Open the EXCEL.
Enter x, y, and z in different columns.
On Data tab in analysis group, click Data Analysis.
Select Anova: Single Factor.
Click OK.
Click in the Input Range box, select x, y, and z.
Click OK.

The output obtained using EXCEL software is shown below:

Modern Business Statistics with Microsoft Office Excel (with XLSTAT Education Edition Printed Access Card) (MindTap Course List), Chapter 13, Problem 34SE

From the output, it is observed that the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If thep-value≤α, reject the null hypothesis H0.

If thep-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference in the ability of the brands to absorb water.