Paper Towel Absorption. In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

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Answer 1

Textbook Question

Chapter 13, Problem 34E

Paper Towel Absorption. In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

Chapter 13, Problem 34E, Paper Towel Absorption. In a completely randomized experimental design, three brands of paper towels

Expert Solution & Answer

To determine

Check whether there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer to Problem 34E

Yes, there appears to be a difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represents the absorbency rate for the three brands.

Assume that, μ1, μ2 and μ3 denote the population means of three brands x, y and z respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha: At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way Anova:

Software procedure:

Step-by-step procedure to obtain One-way Anova using the EXCEL:

Enter the data in an EXCEL sheet.
On Data tab in Analysis group, click Data Analysis.
Select Anova: Single Factor.
Click Ok.
Click in the Input Range box, select the range $A$1: $C$5.
Click in the Output range, select $G$1
Click OK.

Output using the EXCEL software is given below:

Essentials Of Statistics For Business & Economics, Chapter 13, Problem 34E

From the EXCEL output, the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If p-value≤α, reject the null hypothesis H0.

If p-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

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Answer 2

Textbook Question

Chapter 13, Problem 34E

Paper Towel Absorption. In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

Chapter 13, Problem 34E, Paper Towel Absorption. In a completely randomized experimental design, three brands of paper towels

Expert Solution & Answer

To determine

Check whether there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer to Problem 34E

Yes, there appears to be a difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represents the absorbency rate for the three brands.

Assume that, μ1, μ2 and μ3 denote the population means of three brands x, y and z respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha: At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way Anova:

Software procedure:

Step-by-step procedure to obtain One-way Anova using the EXCEL:

Enter the data in an EXCEL sheet.
On Data tab in Analysis group, click Data Analysis.
Select Anova: Single Factor.
Click Ok.
Click in the Input Range box, select the range $A$1: $C$5.
Click in the Output range, select $G$1
Click OK.

Output using the EXCEL software is given below:

Essentials Of Statistics For Business & Economics, Chapter 13, Problem 34E

From the EXCEL output, the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If p-value≤α, reject the null hypothesis H0.

If p-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

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Answer 3

Textbook Question

Chapter 13, Problem 34E

Paper Towel Absorption. In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

Chapter 13, Problem 34E, Paper Towel Absorption. In a completely randomized experimental design, three brands of paper towels

Expert Solution & Answer

To determine

Check whether there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer to Problem 34E

Yes, there appears to be a difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represents the absorbency rate for the three brands.

Assume that, μ1, μ2 and μ3 denote the population means of three brands x, y and z respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha: At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way Anova:

Software procedure:

Step-by-step procedure to obtain One-way Anova using the EXCEL:

Enter the data in an EXCEL sheet.
On Data tab in Analysis group, click Data Analysis.
Select Anova: Single Factor.
Click Ok.
Click in the Input Range box, select the range $A$1: $C$5.
Click in the Output range, select $G$1
Click OK.

Output using the EXCEL software is given below:

Essentials Of Statistics For Business & Economics, Chapter 13, Problem 34E

From the EXCEL output, the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If p-value≤α, reject the null hypothesis H0.

If p-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 13, Problem 34E

Paper Towel Absorption. In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equal-size towels were used, with four sections of towels tested per brand. The absorbency rating data follow. At a .05 level of significance, does there appear to be a difference in the ability of the brands to absorb water?

Chapter 13, Problem 34E, Paper Towel Absorption. In a completely randomized experimental design, three brands of paper towels

Expert Solution & Answer

To determine

Check whether there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer to Problem 34E

Yes, there appears to be a difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represents the absorbency rate for the three brands.

Assume that, μ1, μ2 and μ3 denote the population means of three brands x, y and z respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha: At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way Anova:

Software procedure:

Step-by-step procedure to obtain One-way Anova using the EXCEL:

Enter the data in an EXCEL sheet.
On Data tab in Analysis group, click Data Analysis.
Select Anova: Single Factor.
Click Ok.
Click in the Input Range box, select the range $A$1: $C$5.
Click in the Output range, select $G$1
Click OK.

Output using the EXCEL software is given below:

Essentials Of Statistics For Business & Economics, Chapter 13, Problem 34E

From the EXCEL output, the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If p-value≤α, reject the null hypothesis H0.

If p-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

Check whether there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer to Problem 34E

Yes, there appears to be a difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represents the absorbency rate for the three brands.

Assume that, μ1, μ2 and μ3 denote the population means of three brands x, y and z respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha: At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way Anova:

Software procedure:

Step-by-step procedure to obtain One-way Anova using the EXCEL:

Enter the data in an EXCEL sheet.
On Data tab in Analysis group, click Data Analysis.
Select Anova: Single Factor.
Click Ok.
Click in the Input Range box, select the range $A$1: $C$5.
Click in the Output range, select $G$1
Click OK.

Output using the EXCEL software is given below:

Essentials Of Statistics For Business & Economics, Chapter 13, Problem 34E

From the EXCEL output, the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If p-value≤α, reject the null hypothesis H0.

If p-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer 8

Expert Solution & Answer

To determine

Check whether there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer to Problem 34E

Yes, there appears to be a difference in the ability of the brands to absorb water.

Explanation of Solution

Calculation:

The data represents the absorbency rate for the three brands.

Assume that, μ1, μ2 and μ3 denote the population means of three brands x, y and z respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha: At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way Anova:

Software procedure:

Step-by-step procedure to obtain One-way Anova using the EXCEL:

Enter the data in an EXCEL sheet.
On Data tab in Analysis group, click Data Analysis.
Select Anova: Single Factor.
Click Ok.
Click in the Input Range box, select the range $A$1: $C$5.
Click in the Output range, select $G$1
Click OK.

Output using the EXCEL software is given below:

Essentials Of Statistics For Business & Economics, Chapter 13, Problem 34E

From the EXCEL output, the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If p-value≤α, reject the null hypothesis H0.

If p-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

Check whether there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer 12

Answer to Problem 34E

Yes, there appears to be a difference in the ability of the brands to absorb water.

Answer 13

Explanation of Solution

Calculation:

The data represents the absorbency rate for the three brands.

Assume that, μ1, μ2 and μ3 denote the population means of three brands x, y and z respectively.

The test hypotheses are given below:

Null hypothesis:

H0:μ1=μ2=μ3

Alternative hypothesis:

Ha: At least one of the means is not equal.

It is given that the level of significance as 0.05.

One-way Anova:

Software procedure:

Step-by-step procedure to obtain One-way Anova using the EXCEL:

Enter the data in an EXCEL sheet.
On Data tab in Analysis group, click Data Analysis.
Select Anova: Single Factor.
Click Ok.
Click in the Input Range box, select the range $A$1: $C$5.
Click in the Output range, select $G$1
Click OK.

Output using the EXCEL software is given below:

Essentials Of Statistics For Business & Economics, Chapter 13, Problem 34E

From the EXCEL output, the F-ratio is 7.23 and the p-value is 0.0134.

Decision:

If p-value≤α, reject the null hypothesis H0.

If p-value>α, fail to reject the null hypothesis H0.

Conclusion:

Here, the p-value is less than the level of significance.

That is, p-value(=0.0134)<α(=0.05).

Therefore, the null hypothesis is rejected.

Hence, there is sufficient evidence to infer that there is a significant difference among the mean absorbency ratings for the three brands at α=0.05 level of significance.

Answer 14

Ch. 13.2 - The following data are from a completely...Ch. 13.2 - 2. In a completely randomized design, seven...Ch. 13.2 - 3. Refer to exercise 2. what hypotheses are...Ch. 13.2 - 4. In an experiment designed to test the output...Ch. 13.2 - 5. In a completely randomized design, 12...Ch. 13.2 - Develop the analysis of variance computations for...Ch. 13.2 - 7. Three different methods for assembling a...Ch. 13.2 - 8. Refer to the NCP data in Table 13.4. Set up the...Ch. 13.2 - To study the effect of temperature on yield in a...Ch. 13.2 - Prob. 10E

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Answer to Problem 34E

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