GENERAL,ORGANIC+BIOCHEM (LOOSELEAF)
GENERAL,ORGANIC+BIOCHEM (LOOSELEAF)
10th Edition
ISBN: 9781264035090
Author: Denniston
Publisher: MCG
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Question
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Chapter 13, Problem 2MCP

(a)

Interpretation Introduction

Interpretation:

The statement “Nonanal has a lower melting point than nonane” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(a)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is false because the melting point of nonanal will be higher than nonane due to the presence of strong dipole-dipole attractions in nonanal.

Explanation of Solution

Nonanal is an aldehyde and nonane is an alkane.

The carbonyl group of an aldehyde or a ketone is polar because oxygen is more electronegative than carbon.  This produces a dipole in which the oxygen carries a partial negative charge and the carbon carries a partial positive charge.  Because of the dipole-dipole attractions between molecules are stronger than London dispersion forces, aldehydes and ketones boil at higher temperatures than hydrocarbons of equivalent molar mass.  Hence, the statement “Nonanal has a lower melting point than nonane” is false because the presence of strong dipole-dipole attractions and polar carbonyl group makes the melting point of nonanal higher than nonane.

(b)

Interpretation Introduction

Interpretation:

The statement “Nonanal has a higher boiling point than nonanol” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(b)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is true.

Explanation of Solution

Nonanal is an aldehyde and nonanol is an alcohol.

Alcohols have strong intermolecular hydrogen bonding.  The OH group present in the alcohol allows the molecules to participate in hydrogen bonding.  A larger amount of energy is required to break the intermolecular hydrogen bonding in alcohols hence, they have higher boiling and higher melting points.

Aldehydes have lower boiling points when compared to alcohols, showing the presence of weak intermolecular dipole-dipole forces.  Aldehydes and ketones cannot form hydrogen bond with other aldehydes or ketones due to the absence of oxygen-hydrogen bond in the carbonyl group.

Hence, the statement “Nonanal has a higher boiling point than nonanol” is true.

(c)

Interpretation Introduction

Interpretation:

The statement “nonanal is not soluble in water” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(c)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is true.

Explanation of Solution

Aldehydes with five or fewer carbon atoms are soluble in water.

Nonanal is a saturated fatty aldehyde with chain length containing nine carbon atoms.  The hydrophobic part is non-polar and is insoluble in water.  Therefore, the given statement is true.

(d)

Interpretation Introduction

Interpretation:

The statement “Nonanal is polar” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(d)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is true.

Explanation of Solution

The structure of nonanal is,

GENERAL,ORGANIC+BIOCHEM (LOOSELEAF), Chapter 13, Problem 2MCP , additional homework tip  1

Nonanal consists of carbonyl carbon attached with carbon containing groups.  Because of the presence of polar carbonyl group, nonanal is polar in nature.  Hence, the given statement is true.

(e)

Interpretation Introduction

Interpretation:

The line formula of nonanal has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(e)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given line formula of nonanal is false because it represents octanal.

Explanation of Solution

The given line formula is,

GENERAL,ORGANIC+BIOCHEM (LOOSELEAF), Chapter 13, Problem 2MCP , additional homework tip  2

The above line formula represents octanal.  Therefore, it is false.

The line formula of nonanal is,

GENERAL,ORGANIC+BIOCHEM (LOOSELEAF), Chapter 13, Problem 2MCP , additional homework tip  3

(f)

Interpretation Introduction

Interpretation:

The statement “Nonanal has weaker dispersion forces between molecules than heptanal” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(f)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is true.

Explanation of Solution

The dispersion forces decreases with increase in number of carbon atoms.  Nonanal has nine carbon atoms and heptanal has seven carbon atoms, the dispersion forces present in nonanal would be weaker than that of heptanol.  Therefore, the given statement is true.

(g)

Interpretation Introduction

Interpretation:

The statement “Nonanal is solid at room temperature” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(g)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is false because it appears as liquid at room temperature.

Explanation of Solution

Nonanal is liquid that is characterized by a rose-orange odor.  It is insoluble in water and is found in twenty essential oils including rose and citrus oils and several species of pine oil.

(h)

Interpretation Introduction

Interpretation:

The statement “Oxidation of nonanal would produce a primary alcohol” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(h)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is false because the oxidation of nonanal would produce a carboxylic acid.

Explanation of Solution

Oxidation of nonanal would produce a carboxylic acid named nonanoic acid.  Nonanal is produced by the reduction of primary alcohol (nonanol).

(i)

Interpretation Introduction

Interpretation:

The statement “Nonanal is more oxidized than nonanol” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(i)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is true.

Explanation of Solution

The presence of hydrogen bonding capabilities and the presence of one oxygen atoms along with an extra hydrogen atom makes them more oxidized than nonanol.

Hence, the statement “Nonanal is more oxidized than nonanol” is true.

(j)

Interpretation Introduction

Interpretation:

The statement “The reaction of nonanal with an ethanol molecule would produce an acetal” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(j)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is false because reaction of nonanal with an ethanol molecule would produce hemiacetal.

Explanation of Solution

A hemiacetal is formed when nonanal reacts with one molecule of ethanol.  The given statement is false because acetals are generally produced from two molecules of alcohols with aldehydes/ketones.

(k)

Interpretation Introduction

Interpretation:

The statement “The enol structure of nonanal” has to be predicted as true or false.  If the statement is false, the reason for the false statement has to be described.

(k)

Expert Solution
Check Mark

Answer to Problem 2MCP

The given statement is true.

Explanation of Solution

The keto-enol form of nonanal is,

GENERAL,ORGANIC+BIOCHEM (LOOSELEAF), Chapter 13, Problem 2MCP , additional homework tip  4

Hence, the given statement is true.

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Chapter 13 Solutions

GENERAL,ORGANIC+BIOCHEM (LOOSELEAF)

Ch. 13.2 - Prob. 13.7QCh. 13.2 - Write the condensed formula for each of the...Ch. 13.3 - Draw the structure of the aldehyde synthesized...Ch. 13.3 - Prob. 13.10QCh. 13.4 - Prob. 13.5PPCh. 13.4 - Prob. 13.6PPCh. 13.4 - Prob. 13.7PPCh. 13.4 - Prob. 13.8PPCh. 13.4 - Prob. 13.11QCh. 13.4 - Prob. 13.12QCh. 13.4 - Identify each of the following structures as a...Ch. 13.4 - Identify each of the following structures as a...Ch. 13.4 - Prob. 13.9PPCh. 13 - Prob. 13.15QPCh. 13 - Prob. 13.16QPCh. 13 - Prob. 13.17QPCh. 13 - Prob. 13.18QPCh. 13 - Prob. 13.19QPCh. 13 - Prob. 13.20QPCh. 13 - Prob. 13.21QPCh. 13 - Why do hydrocarbons have lower boiling points than...Ch. 13 - Prob. 13.23QPCh. 13 - Prob. 13.24QPCh. 13 - Prob. 13.25QPCh. 13 - Prob. 13.26QPCh. 13 - Prob. 13.27QPCh. 13 - Prob. 13.28QPCh. 13 - Draw each of the following using condensed...Ch. 13 - Prob. 13.30QPCh. 13 - Prob. 13.31QPCh. 13 - Prob. 13.32QPCh. 13 - Prob. 13.33QPCh. 13 - Prob. 13.34QPCh. 13 - Prob. 13.35QPCh. 13 - Prob. 13.36QPCh. 13 - Prob. 13.37QPCh. 13 - Prob. 13.38QPCh. 13 - Give the IUPAC name for each of the following...Ch. 13 - Give the IUPAC name for each of the following...Ch. 13 - Prob. 13.41QPCh. 13 - Prob. 13.42QPCh. 13 - Prob. 13.43QPCh. 13 - Prob. 13.44QPCh. 13 - Prob. 13.45QPCh. 13 - Prob. 13.46QPCh. 13 - Prob. 13.47QPCh. 13 - Prob. 13.48QPCh. 13 - Prob. 13.49QPCh. 13 - Prob. 13.50QPCh. 13 - Prob. 13.51QPCh. 13 - Prob. 13.52QPCh. 13 - Prob. 13.53QPCh. 13 - Prob. 13.54QPCh. 13 - Prob. 13.55QPCh. 13 - Prob. 13.56QPCh. 13 - Prob. 13.57QPCh. 13 - Prob. 13.58QPCh. 13 - Prob. 13.59QPCh. 13 - Prob. 13.60QPCh. 13 - Prob. 13.61QPCh. 13 - An unknown has been determined to be one of the...Ch. 13 - Prob. 13.63QPCh. 13 - Prob. 13.64QPCh. 13 - Prob. 13.65QPCh. 13 - Prob. 13.66QPCh. 13 - Which of the following compounds would be expected...Ch. 13 - Write an equation representing the reaction of...Ch. 13 - Prob. 13.69QPCh. 13 - Prob. 13.70QPCh. 13 - Prob. 13.71QPCh. 13 - Prob. 13.72QPCh. 13 - Prob. 13.73QPCh. 13 - Prob. 13.74QPCh. 13 - Prob. 13.75QPCh. 13 - Prob. 13.76QPCh. 13 - Prob. 13.77QPCh. 13 - Prob. 13.78QPCh. 13 - Prob. 13.79QPCh. 13 - Prob. 13.80QPCh. 13 - Prob. 13.81QPCh. 13 - Prob. 13.82QPCh. 13 - Prob. 13.83QPCh. 13 - Prob. 13.84QPCh. 13 - Prob. 1MCPCh. 13 - Prob. 2MCPCh. 13 - Prob. 3MCPCh. 13 - Prob. 4MCPCh. 13 - Prob. 6MCPCh. 13 - Prob. 7MCPCh. 13 - Prob. 8MCPCh. 13 - Design a synthesis for each of the following...Ch. 13 - Prob. 10MCPCh. 13 - Prob. 12MCP
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