EBK PRINCIPLES OF ELECTRIC CIRCUITS
10th Edition
ISBN: 9780134880068
Author: Buchla
Publisher: VST
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8.24 In the circuit of Fig. P8.24, is(t) = 0.2sin105t A,R = 20 W, L = 0.1 mH, and C = 2 μF. Show that the sum ofthe complex powers for the three passive elements is equal to thecomplex power of the source.
3. VEB (on) 0.7 V, VEC (sat) = 0.2 V, and ẞ = 150. RB = 50 kQ, Rc = 2 kQ, and Vcc =
5 V.
a) Find the range of V₁ for the cut-off. Forward active, and saturation regions. (20
points)
b) Draw the voltage transfer characteristic (VTC) graph. (10 points)
Vcc
VEB
V₁
RB
www
。 Vo
Rc
Figure 3
2-1) Lathi & Ding prob. 2.5-2 For the signals y(t) and x(t) shown below, find the component of the form
y(t) contained in x(t). In other words, find the optimum value of c in the approximation x(t) = cy(t) so that
the error signal energy is minimum. Also compute the error signal energy.
y(t)
x(t)
0
1
0
1
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- 1. Is1 = 2ls2 = 4 × 10-16 A, B₁ = ẞ2 = 100, and R₁ = 5 kQ. Find the VB such that lx = 1 mA. (30 points) R1 ww Q2 + VB Figure 1arrow_forward2-2) Lathi & Ding prob. 2.6-1 2.6-1 Find the correlation coefficient p between of signal x(t) and each of the four pulses g1(1), 82(1), 83(1), and g4(f) shown in Fig. P2.6-1. To provide maximum margin against the noise along the transmission path, which pair of pulses would you select for a binary communication? Figure P.2.6-1 x(f) (a) 8(1) (b) 82(1) (c) 1 1 sin 2πt sin 4πt -sin 2 0 0.707 83(1) 0 1 (d) 0 M P 0.707 84(1) (e) 0 0.5 -0.707arrow_forward2. Determine the operation point and the small-signal model of Q₁ for each of the circuits shown in Fig. 2. Assume Is = 8 × 10-16 A, B = 100 and VA = ∞. a) 20 points b) 20 points 0.8 V RC 50 Ω + Vcc = 2.5 V 4A" Figure 2-a Rc1kQ + Vcc = 2.5 V Figure 2-barrow_forward
- Please explain in detail how to solve this question. Include steps with calculations and theory. thank youarrow_forwardFinding crystallographic direction Z pt. 2 head pt. 1: ៩ Example 2: pt. 1 x₁ = a, y₁ = b/2, z₁ = 0 pt. 2 x2=-a, y₂ = b, Z₂ = c -a-a b-b/2 c-0 a b c tail => -2, 1/2, 1 Multiplying by 2 to eliminate the fraction -4,1,2 => [412] where the overbar represents a negative index families of directionsarrow_forwardCrystallographic planes Crystallographic planes are denoted by Miller indices. 5b Algorithm for Miller indices 1. Read off intercepts of plane with axes in terms of a, b, c 2. Take reciprocals of intercepts 3. Reduce to smallest integer values 4. Enclose in parentheses, no commas. 353 1/3 1/5 1/3 535 (535) In the cubic system, a plane and a direction with the same indices are orthogonal. E.g. [100] direction is perpendicular to (100) plane. Correspondingly, [123] direction is perpendicular to (123) plane. [2,3,3] Plane intercepts axes at 3a, 2b, 2c 2 11 1 Reciprocal numbers are: 3'2'2 b. Indices of the plane (Miller): (2,3,3) 2 a Indices of the direction: [2,3,3] X (200) (100) (110) (111) (100) Indices of crystallographic plane can be found from cross product of indices of any two non-parallel directions in this plane.arrow_forward
- Crystallographic positions Crystallographic position is denoted by three numbers, which are coefficients of the position vector, e.g. ½½½ for the red atom. Here the 'new' atom is at a/2 + b/2 + c/2 Silicon crystal has so-called "diamond type lattice". Each Si atom has 4 nearest neighbors. Diamond lattice starts with a FCC lattice and then adds four additional INTERNAL atoms at locations r = a/4+b/4+c/4 away from each of the atoms. In other words, diamond lattice is formed by two FCC lattices sifted by the vector r.arrow_forwardfind the answers for this prelabarrow_forwardQ2: (30 Marks) Design a DC/DC converter that produce output waveforms that shown in figures below from a fixed DC source of 20 volts. Vo (Volt) 14.1 IL (Amp) 13.9 2.25 1.75 † (msec) Output voltage 0.18 0.2 t (msec) L 0.214 0.22 Output currentarrow_forward
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