Physics for Scientists and Engineers
10th Edition
ISBN: 9781337553278
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 13, Problem 26AP
To determine
The argument that shows that the gravity at the surface of a neutron star is more than sufficient to provide the centripetal acceleration.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Astronomers discover a binary system with a period of 90 days. Both stars have a mass
twice that of the Sun. How far apart are the two stars?
Both stars revolve around
the center of mass in an
orbit with radius r.
F2oni
d=ar
Fron2
The distance between the stars is 2r.
What is the average density of a neutron star that has the same mass as the sun but a radius of only 86.31 km? Express your answer in the proper SI unit and without scientific notation.
A visual binary is composed of two stars A and B. This visual binary has a rotation period
of 59.94 years and a distance of 3.64 pc from Earth. Assuming that the plane of the orbit
is in the plane of the sky, the true angular extent of the semi-major axis is 7.61". The ratio
of the distances of A and B from the centre of mass is aд/aB = 0.6. Find the masses of
each member of the system.
NOTE: to keep the calculation easier you should express the mass of the system in units
of solar masses.
Chapter 13 Solutions
Physics for Scientists and Engineers
Ch. 13.1 - A planet has two moons of equal mass. Moon 1 is in...Ch. 13.2 - Superman stands on top of a very tall mountain and...Ch. 13.4 - An asteroid is in a highly eccentric elliptical...Ch. 13.6 - Prob. 13.4QQCh. 13 - In introductory physics laboratories, a typical...Ch. 13 - During a solar eclipse, the Moon, the Earth, and...Ch. 13 - Determine the order of magnitude of the...Ch. 13 - Prob. 4PCh. 13 - Review. Miranda, a satellite of Uranus, is shown...Ch. 13 - (a) Compute the vector gravitational field at a...
Ch. 13 - A spacecraft in the shape of a long cylinder has a...Ch. 13 - An artificial satellite circles the Earth in a...Ch. 13 - Prob. 9PCh. 13 - A particle of mass m moves along a straight line...Ch. 13 - Use Keplers third law to determine how many days...Ch. 13 - Prob. 12PCh. 13 - Suppose the Suns gravity were switched off. The...Ch. 13 - (a) Given that the period of the Moons orbit about...Ch. 13 - How much energy is required to move a 1 000-kg...Ch. 13 - An object is released from rest at an altitude h...Ch. 13 - A system consists of three particles, each of mass...Ch. 13 - Prob. 18PCh. 13 - A 500-kg satellite is in a circular orbit at an...Ch. 13 - Prob. 20PCh. 13 - Prob. 21PCh. 13 - Prob. 22PCh. 13 - Ganymede is the largest of Jupiters moons....Ch. 13 - Prob. 24APCh. 13 - Voyager 1 and Voyager 2 surveyed the surface of...Ch. 13 - Prob. 26APCh. 13 - Prob. 27APCh. 13 - Why is the following situation impossible? A...Ch. 13 - Let gM represent the difference in the...Ch. 13 - Prob. 30APCh. 13 - Prob. 31APCh. 13 - Prob. 32APCh. 13 - Prob. 33APCh. 13 - Two spheres having masses M and 2M and radii R and...Ch. 13 - (a) Show that the rate of change of the free-fall...Ch. 13 - Prob. 36APCh. 13 - Studies of the relationship of the Sun to our...Ch. 13 - Review. Two identical hard spheres, each of mass m...Ch. 13 - Prob. 39APCh. 13 - Prob. 40APCh. 13 - Prob. 41APCh. 13 - Prob. 42APCh. 13 - As thermonuclear fusion proceeds in its core, the...Ch. 13 - Two stars of masses M and m, separated by a...Ch. 13 - The Solar and Heliospheric Observatory (SOHO)...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- How close, r, to the center of a neutron star would a manned satellite be orbiting if it were at the location where the gravitational force from the star equaled the gravitational force of the Earth's surface? RN = neutron star radius = 1 × 104 kmM N = neutron star mass = 3 × 1030 kgG = universal gravitational constant = 6.67 × 10-11 N m2 / kg2g⊕ = Earth gravitational acceleration = 9.807 m/s²arrow_forwardDetermining the orbit of the two stars of Kepler-34, also called A and B. These two stars together are called a binary. A) Assume that star A has a mass of 1 solar mass and star B also has a mass of 1 solar mass. The semi major axis is 0.23 AU and the eccentricty is 0.53. What is the orbital period of the stellar A-B binary in days? Ignore the (much less massive) planet and focus on the orbit of the binary. B) Now let's consider the orbit of the planet, called "b". Since the planet orbits some distance away from the stars, it is an acceptable approximation to pretend like the stellar binary is like a single star with a mass that is the sum of the masses of stars A and B and that the mass of planet "b" is very small, calculate the semi-major axis in AU of the planet's orbit with a period of 289 days. (note: I think for this problem you are supposed to use Newton's version of Kepler's third law P2= 4π2/G(M1-M2)x a3 but, I'm not sure if that's the right thing to do). 1 solar mass= 2 x…arrow_forwardIf a neutron star has a radius of 12 km and rotates 1,352 times a second, what is the speed at which a point on the surface at the neutron star's equator is moving? Express your answer as a fraction of the speed of light. (Note: The speed of light is 3 ✕ 105 km/s.)arrow_forward
- What is the answer below if the radius of the neutron star is 29.894 km? (express your answer in the proper SI unit and without scientific notation) What is the average density of a neutron star that has the same mass as the sun but a radius of only 20.0 km?arrow_forwardThe star HD 69830's mass is 1.7 ✕ 1030 kg, its radius is 6.3 ✕ 105 km, and it has a rotational period of approximately 35 days. If HD 69830 should collapse into a white dwarf of radius 7.8 ✕ 103 km, what would its period (in s) be if no mass were ejected and a sphere of uniform density can model HD 69830 both before and after?arrow_forwardA star has a period of P = 37 days. It has a radius of 5.7 times the radius of the sun. Calculate it's equatorial speed Vrot. Answer: Okm/s Om/s Check A star has a radius of 5.7 times the radius of the sun and a mass of 18 times the mass of the sun. It rotates at 0.7 of the critical speed W, the speed at which it's surface at the equator is actually in orbit. Recall Vrot is calculated at the equator and W= Vrot/Vorb Calculate it's period P. Answer: Odays Ohours Oseconds Checkarrow_forward
- Plasketts binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (Fig. P11.19). Assume the orbital speed of each star is |v|=220km/s and the orbital period of each is 14.4 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 1030 kg.)arrow_forwardIf the radius of the neutron star is 85.074 km, what is the average density of a neutron star that has the same mass as the sun but a radius of only 20.0 km? (express your answer in the proper SI unit and without scientific notation)arrow_forwardWhat is the average density of a neutron star that has the same mass as the sun but a radius of only 49.665 km? (Pls state the answer in the proper SI unit and without scientific notation)arrow_forward
- The Algol binary system consists of a 3.7 Msun star and a 0.8 Msun star with an orbital period of 2.87 days. Using Newton’s version of Kepler’s Third Law, calculate the distance, a, between the two stars. Compare that to the size of Betelgeuse (you’ll need to look that up). Newton’s Version of Kepler’s Law: (M1 + M2) P2 = (4p2 /G) a3 Rearrange the equation to solve for a. Pi, p, is equal to 3.14. IMPORTANT NOTE: Google the value of G (the Universal Gravitational Constant) or look it up in your text. NOTICE THE UNITS. You must convert every distance and time in your equation to the same units, otherwise, you’ll get an incorrect answer. That means you must convert distances to meters, solar masses to kilograms, and time to seconds. When you compare your value to the size of Betelgeuse, it will also help that they are in the same units.arrow_forwardWhat is the Schwarzschild radius of a star with a mass of z × 10 Mun? The answer is in 106m. So if you calculated an answer like 157,895,250 convert it like this: 106 157, 895, 250 × 157.9 and that is what you will input 100000 z =2.57 y =3 M Sun = 2 × 10³⁰ kg =arrow_forwardA Type Ia supernova is observed and achieves an apparent magnitude of m = 19.89 at peak brightness. The absolute magnitudes of Type Ia supernovae at peak brightness are known to be M=−19. Determine the distance to the supernovae in units of Mpc.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Stars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill
Foundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
Stars and GalaxiesPhysicsISBN:9781305120785Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Stars and Galaxies (MindTap Course List)
Physics
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Foundations of Astronomy (MindTap Course List)
Physics
ISBN:9781337399920
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Stars and Galaxies
Physics
ISBN:9781305120785
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning