Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card
Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card
6th Edition
ISBN: 9781305717367
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
Question
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Chapter 13, Problem 24E
Interpretation Introduction

(a)

Interpretation:

The electron-pair geometry for each carbon atom in CH3CH2COOH is to be explained and the Lewis diagram for the molecule is to be drawn.

Concept introduction:

The electron pairs in Lewis diagrams repel each other in real molecule and thus they distribute themselves in positions around the central atoms which are far away from one another. This arrangement of electron pairs is called electron-pair geometry. The electron pairs may be shared in covalent bond, or they may be lone pairs.

Expert Solution
Check Mark

Answer to Problem 24E

The Lewis diagram for the molecule CH3CH2COOH is shown below.

Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card, Chapter 13, Problem 24E , additional homework tip  1

The electron pair geometry for the carbon atoms CH3, and CH2 are tetrahedral and for the carbon COOH is trigonal planar.

Explanation of Solution

To write the Lewis diagram for a compound, first the number of valence electrons is to be calculated. In the molecule, CH3CH2COOH, each carbon has four valence electrons, each hydrogen has one valence electron, and each oxygen has six valence electrons. The total number of valence electron for the molecule CH3CH2COOH is calculated below.

Totalnumberofvalenceelectron=(3×4+6×1+6×2)e=30e

The atom which is least electronegative and lesser in number is the central atom. In CH3CH2COOH, carbon is least electronegative element and is lesser in number. Therefore, carbon is the central atom. Carbon is bonded with hydrogen atoms and oxygen atom. In Lewis diagram, each electron is placed around the atom such that the octet rule is obeyed. Therefore, the Lewis diagram of CH3CH2COOH is shown below.

Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card, Chapter 13, Problem 24E , additional homework tip  2

Figure 1

The electron-pair geometry depends on the number of electron pairs around the central atoms. In the molecule CH3CH2COOH, there are four electron-pairs around the each carbon atom shown as CH3, and CH2, and there are three electron-pairs for the carbon atom in COOH due to the presence of (C=O) double bond. Therefore, the electron pair geometry for the carbon atoms CH3, and CH2 are tetrahedral and for the carbon COOH is trigonal planar.

Conclusion

The Lewis diagram for the molecule CH3CH2COOH is shown in the Figure 1. The electron pair geometry for the carbons CH3, and CH2 are tetrahedral and for the carbon COOH is trigonal planar.

Interpretation Introduction

(b)

Interpretation:

The molecular geometry predicted by the valence shell electron-pair repulsion theory for each carbon atom in the molecule CH3CH2COOH is to be explained and the Lewis diagram for the molecule is to be drawn.

Concept introduction:

Molecular geometry is the precise term that is used to describe the shape of molecules and arrangement of atoms around the central atom. The molecular geometry of a molecule is predicted by valence shell electron-pair repulsion theory or in short VSEPR theory. VSEPR theory applies to substances in which a second period element is bonded to two, three, four, or other atoms.

Expert Solution
Check Mark

Answer to Problem 24E

The Lewis diagrams for CH3CH2COOH is shown below.

Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card, Chapter 13, Problem 24E , additional homework tip  3

The molecular geometry is tetrahedral for the carbons CH3, and CH2 and trigonal planar for the carbon COOH.

Explanation of Solution

To write the Lewis diagram for a compound first the number of valence electrons is to be calculated. In the molecule CH3CH2COOH, each carbon has four valence electrons, each hydrogen has one valence electron, and each oxygen has six valence electrons. The total number of valence electron for the molecule CH3CH2COOH is calculated below.

Totalnumberofvalenceelectron=(3×4+6×1+6×2)e=30e

The atom which is least electronegative and lesser in number is the central atom. In CH3CH2COOH carbon is least electronegative element and is lesser in number. Therefore, carbon is the central atom. Carbon is bonded with hydrogen atoms and oxygen atom. In Lewis diagram each electron is placed around the atom such that the octet rule is obeyed. Therefore, the Lewis diagram of CH3CH2COOH is shown below.

Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card, Chapter 13, Problem 24E , additional homework tip  4

Figure 1

The molecular geometry depends on the number of electron pairs as well as number of unpaired electron on the central atoms. In the molecule CH3CH2COOH, there are four electron-pairs around the each carbon atom shown as CH3, and CH2; and there are three electron-pairs for the carbon atom in COOH due to the presence of (C=O) double bond and no lone pair present on the central atoms. Therefore, the molecular geometry would be same as electron-pair geometry that is tetrahedral for the carbon atoms CH3, and CH2 and trigonal planar for the carbon COOH.

Conclusion

The Lewis diagram for the molecule CH3CH2COOH is shown in the Figure 1. The molecular geometry is tetrahedral for the carbons CH3, and CH2 and trigonal planar for the carbon COOH.

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Chapter 13 Solutions

Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card

Ch. 13 - Prob. 11ECh. 13 - Prob. 12ECh. 13 - Prob. 13ECh. 13 - Prob. 14ECh. 13 - Prob. 15ECh. 13 - Prob. 16ECh. 13 - Prob. 17ECh. 13 - Prob. 18ECh. 13 - Prob. 19ECh. 13 - Prob. 20ECh. 13 - Prob. 21ECh. 13 - Prob. 22ECh. 13 - Prob. 23ECh. 13 - Prob. 24ECh. 13 - Prob. 25ECh. 13 - Prob. 26ECh. 13 - Prob. 27ECh. 13 - Prob. 28ECh. 13 - Prob. 29ECh. 13 - Prob. 30ECh. 13 - Prob. 31ECh. 13 - Prob. 32ECh. 13 - Prob. 33ECh. 13 - Prob. 34ECh. 13 - Prob. 35ECh. 13 - Prob. 36ECh. 13 - Prob. 37ECh. 13 - Prob. 38ECh. 13 - Prob. 39ECh. 13 - Prob. 40ECh. 13 - Prob. 41ECh. 13 - Prob. 42ECh. 13 - Prob. 43ECh. 13 - Prob. 44ECh. 13 - Is the carbon tetrachloride molecule, CCl4, which...Ch. 13 - Prob. 46ECh. 13 - Describe the shapes and compare the polarities of...Ch. 13 - Prob. 48ECh. 13 - Prob. 49ECh. 13 - Prob. 50ECh. 13 - Prob. 51ECh. 13 - Prob. 52ECh. 13 - Prob. 53ECh. 13 - Prob. 54ECh. 13 - Prob. 55ECh. 13 - Prob. 56ECh. 13 - Prob. 57ECh. 13 - Prob. 58ECh. 13 - Prob. 59ECh. 13 - Prob. 60ECh. 13 - Prob. 61ECh. 13 - Prob. 62ECh. 13 - Prob. 63ECh. 13 - Prob. 64ECh. 13 - Prob. 65ECh. 13 - Prob. 66ECh. 13 - Prob. 67ECh. 13 - Classify each of the following statements as true...Ch. 13 - Prob. 69ECh. 13 - Draw Lewis diagrams for these five acids of...Ch. 13 - Prob. 71ECh. 13 - Prob. 72ECh. 13 - Describe the shapes of C2H6 and C2H4. In doing so,...Ch. 13 - Prob. 74ECh. 13 - Prob. 75ECh. 13 - C4H10O is the formula of diethyl ether. The same...Ch. 13 - Prob. 77ECh. 13 - Prob. 78ECh. 13 - Draw Lewis diagrams for water and dihydrogen...Ch. 13 - Prob. 2PECh. 13 - Prob. 3PECh. 13 - Prob. 4PECh. 13 - Prob. 5PECh. 13 - What is the Lewis diagram of butane, C4H10?Ch. 13 - Prob. 7PECh. 13 - Prob. 8PECh. 13 - Prob. 9PECh. 13 - Prob. 10PECh. 13 - In the gas phase, tin (II) chloride is a...Ch. 13 - Prob. 12PECh. 13 - Determine the molecular geometry around each...Ch. 13 - Describe the molecular geometry around each carbon...Ch. 13 - Is the difluoromethane molecule polar or nonpolar?...Ch. 13 - Prob. 1LDRECh. 13 - Prob. 2LDRECh. 13 - Prob. 3LDRECh. 13 - Prob. 4LDRECh. 13 - Prob. 5LDRECh. 13 - Prob. 6LDRECh. 13 - Prob. 7LDRECh. 13 - Prob. 8LDRECh. 13 - Prob. 9LDRECh. 13 - Prob. 10LDRE
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