COMPTIA A+ GUIDE TO IT TECH SUPPORT
10th Edition
ISBN: 9780357466810
Author: ANDREWS
Publisher: CENGAGE L
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Chapter 13, Problem 1TC
Explanation of Solution
Given:
Routine maintenance tasks.
To find: The routine maintenance activities, from the most to the least important, while securing the computer.
Solution:
Routine maintenance for a computer involves taking regular steps that make the computer faster, more secure and less cluttered.
The device benefits from antivirus software, such as Windows Defender or Malwarebytes, which can search for files, install and open them in real-time. The role of PC management is to help protect the system from malicious files that can slow down the computer, delete valuable system files or lead to password theft and other personal information loss. Therefore, verifying anti-malware settings is the most securing part of a computer.
Installing updates to the
File sharing is a network for public or private information sharing with different accessibility rates. File sharing enables a limited number of the individuals to read, update or modify a file based on the type of authority provided by the file sharer, depending on the accessibility privileges. Storage of a certain number of files per client per account is usually allocated by file-sharing services.
Temporary internet files, downloaded files and cache files build up as used device and leave less space in the hard drive. Using applications such as the built-in Windows Disk, Cleanup and third-party software such as Mac CCleaner can find and clear these files.
Hence, a, c, b, and d is the correct order.
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Students have asked these similar questions
Please run the following program and answer the questions.
#include
int main(void)
{
int arr[6]
=
int *pointer
pointer
*pointer
=
{10, 20, 30, 40, 50, 60};
=
&arr[0];
pointer + 2;
= 5 ;
pointer++;
*pointer
-
(*pointer) 5 ;
pointer++;
*pointer
* (pointer+1)
-
5%;
return 0;
1. [10 pts] Please list the values of elements in array arr after line 8 (*pointer
why.
=
5; ) and explain
>
Comparable
Method
- methodName: String
-priority: int
+ Method()
+ Method(methodName: String, priority: int)
+ abstract specificWay(): void
+ Getters and setters for all fields
compareTo(otherMethod: Method): int
+ toString(): String
ReadMethod
- language: String
+ ReadMethod()
+ ReadMethod(methodName: String,
priority: int, language: String)
+ specificWay(): void
+ Getters and setters for language
+ toString(): String
Part 1.1. Implement the abstract class Method implements Comparable interface according to its UML
diagram. Add comments stating where data fields, constructors, toString(), and other methods are (if
any). Neither method should have an empty body unless abstract methods.
1. two constructors (default and the constructor with all fields)
2. getters and setters for all fields (methodName and priority).
3. toString() method: modify by yourself to match the example output.
4. Abstract method void specificWay().
5. Implement compara To(Method otherMethod) to compare…
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int ll_has_cycle (node *first)
if (first
NULL) return 0;
node *head = first%;B
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head =
head->next;B
return 0;
void test_11_has_cycle() {
int i;
node nodes [6] ;
for (i =
0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value
i;
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
&nodes [3];
nodes [3] .next
nodes [4] .next
& nodes [4];
NULL;
nodes [5] .next
&nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has %s cycle\n\n", 11_has_cycle (&nodes[0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s cycle\n\n",…
Chapter 13 Solutions
COMPTIA A+ GUIDE TO IT TECH SUPPORT
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