Physical Science (12th Edition), Standalone Book
12th Edition
ISBN: 9781260150544
Author: Bill W. Tillery
Publisher: McGraw Hill Education
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Question
Chapter 13, Problem 1AC
To determine
Natural radioactivity is a result of which of the following actions:
adjustments to balance nuclear attractions and repulsions.
experiments with human-made elements.
absorption of any type of
a mass defect of the nucleus.
Expert Solution & Answer
Answer to Problem 1AC
Solution:
Option (a) is correct.
Explanation of Solution
Introduction:
Radioactivity refers to the disintegration or the breaking of the unstable nucleus of heavier elements. Natural radioactivity means that an element without any interference of a foreign energy breaks and converts into different elements.
Explanation:
Reason for correct option:
As the nuclei become heavier, generally more unstable, the number of protons and neutrons increases the size of the atom. It increases to such an extent that the strong nuclear force cannot bear the force of repulsions of the protons and the nucleus breaks.
This phenomenon is known as radioactivity, which is necessary to stabilize the nuclei of the heavier elements to adjust the nuclear attractions and repulsions.
Hence, option (a) is correct.
Reason for incorrect options:
Natural radioactive decay happens in all elements with atomic number greater than 83, wherein there are various natural occurring elements in which radioactive decay occurs.
Hence, option (b) is incorrect.
Without any radiationabsorption, the elements also undergo radioactive decay.
Hence, option (c) is incorrect.
Radioactive decay is not a mass defect of the nucleus as elements with a perfect mass number also decays.
Hence, option (d) is incorrect.
Conclusion:
The natural radioactivity is the adjustment to balance out the nuclear attractions and repulsions in heavier nucleus elements.
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Three charged particles are located at the corners of an equilateral triangle as shown in the figure below (let q = 2.20 µC, and L = 0.810 m). Calculate the total electric force on the 7.00-µC charge.
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(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 9.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol.
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Chapter 13 Solutions
Physical Science (12th Edition), Standalone Book
Ch. 13 - Prob. 1ACCh. 13 - Prob. 2ACCh. 13 - Prob. 3ACCh. 13 - Prob. 4ACCh. 13 - Prob. 5ACCh. 13 - Prob. 6ACCh. 13 - Prob. 7ACCh. 13 - Prob. 8ACCh. 13 - Prob. 9ACCh. 13 - Prob. 10AC
Ch. 13 - Prob. 11ACCh. 13 - Prob. 12ACCh. 13 - Prob. 13ACCh. 13 - Prob. 14ACCh. 13 - Prob. 15ACCh. 13 - Prob. 16ACCh. 13 - Prob. 17ACCh. 13 - Prob. 18ACCh. 13 - Prob. 19ACCh. 13 - Prob. 20ACCh. 13 - Prob. 21ACCh. 13 - Prob. 22ACCh. 13 - Prob. 23ACCh. 13 - Prob. 24ACCh. 13 - Prob. 25ACCh. 13 - Prob. 26ACCh. 13 - Prob. 27ACCh. 13 - Prob. 28ACCh. 13 - Prob. 29ACCh. 13 - Prob. 30ACCh. 13 - Prob. 31ACCh. 13 - Prob. 32ACCh. 13 - Prob. 33ACCh. 13 - Prob. 34ACCh. 13 - Prob. 35ACCh. 13 - Prob. 36ACCh. 13 - Prob. 37ACCh. 13 - Prob. 38ACCh. 13 - Prob. 39ACCh. 13 - Prob. 40ACCh. 13 - Prob. 41ACCh. 13 - Prob. 42ACCh. 13 - Prob. 43ACCh. 13 - Prob. 44ACCh. 13 - Prob. 45ACCh. 13 - Prob. 46ACCh. 13 - Prob. 1QFTCh. 13 - Prob. 2QFTCh. 13 - Prob. 3QFTCh. 13 - Prob. 4QFTCh. 13 -
5. What is a half-life? Give an example of the...Ch. 13 - Prob. 6QFTCh. 13 - Prob. 7QFTCh. 13 -
8. What is meant by background radiation? What is...Ch. 13 - Prob. 9QFTCh. 13 - What is a mass defect? How is it related to the...Ch. 13 - Prob. 11QFTCh. 13 - Prob. 1FFACh. 13 - Prob. 2FFACh. 13 -
3. Make up a feasible explanation for why some...Ch. 13 - Prob. 4FFACh. 13 - Prob. 5FFACh. 13 - Prob. 6FFACh. 13 - Prob. 7FFACh. 13 - Prob. 1IICh. 13 - Prob. 1PEACh. 13 - Prob. 2PEACh. 13 - Prob. 3PEACh. 13 - Prob. 4PEACh. 13 - Prob. 5PEACh. 13 - Prob. 6PEACh. 13 - Prob. 1PEBCh. 13 - Prob. 2PEBCh. 13 -
3. Predict if the nuclei in exercise 1 are...Ch. 13 - Prob. 4PEBCh. 13 - Prob. 5PEBCh. 13 -
6. If the half-life of cesium–137 is 30 years,...
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