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Bundle: Welding: Principles and Applications, 8th + MindTap Welding, 4 terms (24 months) Printed Access Card
8th Edition
ISBN: 9781337219426
Author: Larry Jeffus
Publisher: Cengage Learning
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Textbook Question
Chapter 13, Problem 14R
What is the purpose of the root pass?
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The volume of 1 kg of helium in a piston–cylinder device is initially 5 m3. Now helium is compressed to 3 m3 while its pressure is maintained constant at 130 kPa. Determine the initial and final temperatures of helium as well as the work required to compress it, in kJ. The gas constant of helium is R = 2.0769 kJ/kg·K.
The initial temperature of helium is K.
The final temperature of helium is K.
The work required to compress helium is kJ.
A piston-cylinder device initially contains 0.4 kg of nitrogen gas at 160 kPa and 140°C. Nitrogen is now expanded isothermally to a
pressure of 80 kPa. Determine the boundary work done during this process. The properties of nitrogen are R= 0.2968 kJ/kg-K and k=
1.4.
N₂
160 kPa
140°C
The boundary work done during this process is
KJ.
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Required information
An abrasive cutoff wheel has a diameter of 5 in, is 1/16 in thick, and has a 3/4-in bore. The wheel weighs 4.80 oz and
runs at 11,700 rev/min. The wheel material is isotropic, with a Poisson's ratio of 0.20, and has an ultimate strength of 12
kpsi.
Choose the correct equation from the following options:
Multiple Choice
о
σmax=
(314) (4r2 — r²)
-
о
σmax = p² (3+) (4r² + r²)
16
σmax =
(314) (4r² + r²)
σmax =
(314) (4² - r²)
Chapter 13 Solutions
Bundle: Welding: Principles and Applications, 8th + MindTap Welding, 4 terms (24 months) Printed Access Card
Ch. 13 - Why is it important to make sure that an FCA...Ch. 13 - What major safety concerns should an FCA welder be...Ch. 13 - Why should the FCA welding practice plates be...Ch. 13 - Why should the FCA welds be of substantial length?Ch. 13 - What must be done to a shielding gas cylinder...Ch. 13 - What can happen to the wire if the conduit is...Ch. 13 - Why is it a good idea for a new student welder to...Ch. 13 - Why is the curl in the wire end straightened out?Ch. 13 - What problems can a high-feed roller pressure...Ch. 13 - Referring to Table 13-1, answer the following a....
Ch. 13 - What are the disadvantages of beveling plates for...Ch. 13 - What is the maximum plate thickness that an FCS...Ch. 13 - What is the smallest V-groove angle that can be...Ch. 13 - What is the purpose of the root pass?Ch. 13 - Why is the FCA welding process not used for...Ch. 13 - Why should convex weld faces be avoided?Ch. 13 - What bead pattern is best for overhead welds?Ch. 13 - Why is the appearance of the cover pass so...Ch. 13 - What are the visual inspection standard's...Ch. 13 - Why is the backing strip 2 in. (50 mm) longer than...Ch. 13 - Why should there be a space between the plates...Ch. 13 - What would a small notch at the root weld's...Ch. 13 - What changes should be made in the setup for...Ch. 13 - What problem must be overcome if the amperage and...Ch. 13 - How can higher welding speeds help control...Ch. 13 - How can spatter buildup on the welding gun be...
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