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High School Math Algebra EP ALGEBRA 2-COMMON CORE-ONLINE ACCESS

To state: An algebraic expression that models the situation: Jenny had $130, but she spends $10 per week. The resultant algebraic expression is 130 − 10 w . Given information: The given statement is Jenny had $130, but she spends $10 per week. Explanation: Consider the definition of algebraic expression: A mathematical phrase that includes a combination of numbers and variables using the mathematical operations is known as an algebraic expression. The same statement can be expressed in algebra by writing it using numbers, variables, and mathematical operations. Starting amount is $130. Amount spent per week is $10. Assume the number of week is w . Now Relate: Starting minus amount spent times number of weeks. Write the expression: 130 − 10 ⋅ w = 130 − 10 w Therefore, 130 − 10 w is the resultant algebraic expression.

To state: An algebraic expression that models the situation: Jenny had $130, but she spends $10 per week. The resultant algebraic expression is 130 − 10 w . Given information: The given statement is Jenny had $130, but she spends $10 per week. Explanation: Consider the definition of algebraic expression: A mathematical phrase that includes a combination of numbers and variables using the mathematical operations is known as an algebraic expression. The same statement can be expressed in algebra by writing it using numbers, variables, and mathematical operations. Starting amount is $130. Amount spent per week is $10. Assume the number of week is w . Now Relate: Starting minus amount spent times number of weeks. Write the expression: 130 − 10 ⋅ w = 130 − 10 w Therefore, 130 − 10 w is the resultant algebraic expression.

Solution Summary: The author states that an algebraic expression that models the situation is 130-10w.

EP ALGEBRA 2-COMMON CORE-ONLINE ACCESS

EP ALGEBRA 2-COMMON CORE-ONLINE ACCESS

15th Edition

ISBN: 9780133318050

Author: Charles

Publisher: PH SCHOOL

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Concept explainers

A percentage is a number indicated as a fraction of 100. It is a dimensionless number often expressed using the symbol %.

Algebraic Expressions

In mathematics, an algebraic expression consists of constant(s), variable(s), and mathematical operators. It is made up of terms.

Numbers are some measures used for counting. They can be compared one with another to know its position in the number line and determine which one is greater or lesser than the other.

Before we begin to understand the subtraction of algebraic expressions, we need to list out a few things that form the basis of algebra.

Before we begin to understand the addition of algebraic expressions, we need to list out a few things that form the basis of algebra.

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Expert Solution & Answer

Chapter 1.3, Problem 13PPSE

Solution

To state: An algebraic expression that models the situation: Jenny had $130, but she spends $10 per week.

The resultant algebraic expression is 130−10w .

Given information:

The given statement is Jenny had $130, but she spends $10 per week.

Explanation:

Consider the definition of algebraic expression:

A mathematical phrase that includes a combination of numbers and variables using the mathematical operations is known as an algebraic expression.

The same statement can be expressed in algebra by writing it using numbers, variables, and mathematical operations.

Starting amount is $130.

Amount spent per week is $10.

Assume the number of week is w .

Now Relate: Starting minus amount spent times number of weeks.

Write the expression:

130−10⋅w=130−10w

Therefore, 130−10w is the resultant algebraic expression.

Chapter 1.3, Problem 12PPSE

Chapter 1.3, Problem 14PPSE

Chapter 1 Solutions

EP ALGEBRA 2-COMMON CORE-ONLINE ACCESS

Ch. 1.1 - Prob. 1LC Ch. 1.1 - Prob. 2LC Ch. 1.1 - Prob. 3LC Ch. 1.1 - Prob. 4LC Ch. 1.1 - Prob. 5LC Ch. 1.1 - Prob. 6LC Ch. 1.1 - Prob. 7LC Ch. 1.1 - Prob. 8PPSE Ch. 1.1 - Prob. 9PPSE Ch. 1.1 - Prob. 10PPSE

Ch. 1.1 - Prob. 11PPSE Ch. 1.1 - Prob. 12PPSE Ch. 1.1 - Prob. 13PPSE Ch. 1.1 - Prob. 14PPSE Ch. 1.1 - Prob. 15PPSE Ch. 1.1 - Prob. 16PPSE Ch. 1.1 - Prob. 17PPSE Ch. 1.1 - Prob. 18PPSE Ch. 1.1 - Prob. 19PPSE Ch. 1.1 - Prob. 20PPSE Ch. 1.1 - Prob. 21PPSE Ch. 1.1 - Prob. 22PPSE Ch. 1.1 - Prob. 23PPSE Ch. 1.1 - Prob. 24PPSE Ch. 1.1 - Prob. 25PPSE Ch. 1.1 - Prob. 26PPSE Ch. 1.1 - Prob. 27PPSE Ch. 1.1 - Prob. 28PPSE Ch. 1.1 - Prob. 29PPSE Ch. 1.1 - Prob. 30PPSE Ch. 1.1 - Prob. 31PPSE Ch. 1.1 - Prob. 32PPSE Ch. 1.1 - Prob. 33PPSE Ch. 1.1 - Prob. 34PPSE Ch. 1.1 - Prob. 35PPSE Ch. 1.1 - Prob. 36PPSE Ch. 1.1 - Prob. 37PPSE Ch. 1.1 - Prob. 38PPSE Ch. 1.1 - Prob. 39PPSE Ch. 1.1 - Prob. 40PPSE Ch. 1.1 - Prob. 41PPSE Ch. 1.1 - Prob. 42PPSE Ch. 1.1 - Prob. 43PPSE Ch. 1.1 - Prob. 44PPSE Ch. 1.1 - Prob. 45PPSE Ch. 1.1 - Prob. 46PPSE Ch. 1.1 - Prob. 47PPSE Ch. 1.1 - Prob. 48PPSE Ch. 1.1 - Prob. 49PPSE Ch. 1.1 - Prob. 50PPSE Ch. 1.1 - Prob. 51PPSE Ch. 1.1 - Prob. 52PPSE Ch. 1.1 - Prob. 53PPSE Ch. 1.1 - Prob. 54PPSE Ch. 1.1 - Prob. 55PPSE Ch. 1.1 - Prob. 56PPSE Ch. 1.1 - Prob. 57PPSE Ch. 1.2 - Prob. 1LC Ch. 1.2 - Prob. 2LC Ch. 1.2 - Prob. 3LC Ch. 1.2 - Prob. 4LC Ch. 1.2 - Prob. 5LC Ch. 1.2 - Prob. 6LC Ch. 1.2 - Prob. 7LC Ch. 1.2 - Prob. 8LC Ch. 1.2 - Prob. 9LC Ch. 1.2 - Prob. 10PPSE Ch. 1.2 - Prob. 11PPSE Ch. 1.2 - Prob. 12PPSE Ch. 1.2 - Prob. 13PPSE Ch. 1.2 - Prob. 14PPSE Ch. 1.2 - Prob. 15PPSE Ch. 1.2 - Prob. 16PPSE Ch. 1.2 - Prob. 17PPSE Ch. 1.2 - Prob. 18PPSE Ch. 1.2 - Prob. 19PPSE Ch. 1.2 - Prob. 20PPSE Ch. 1.2 - Prob. 21PPSE Ch. 1.2 - Prob. 22PPSE Ch. 1.2 - Prob. 23PPSE Ch. 1.2 - Prob. 24PPSE Ch. 1.2 - Prob. 25PPSE Ch. 1.2 - Prob. 26PPSE Ch. 1.2 - Prob. 27PPSE Ch. 1.2 - Prob. 28PPSE Ch. 1.2 - Prob. 29PPSE Ch. 1.2 - Prob. 30PPSE Ch. 1.2 - Prob. 31PPSE Ch. 1.2 - Prob. 32PPSE Ch. 1.2 - Prob. 33PPSE Ch. 1.2 - Prob. 34PPSE Ch. 1.2 - Prob. 35PPSE Ch. 1.2 - Prob. 36PPSE Ch. 1.2 - Prob. 37PPSE Ch. 1.2 - Prob. 38PPSE Ch. 1.2 - Prob. 39PPSE Ch. 1.2 - Prob. 40PPSE Ch. 1.2 - Prob. 41PPSE Ch. 1.2 - Prob. 42PPSE Ch. 1.2 - 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