Chapter 1.1, Problem 18PPSE

Solution

Including process column, complete the table.

Input	$1$	$2$	$3$	$4$	$5$	$6$	…	$n$
Output	$-3$	$-6$	$-9$	$-12$	$\boxed{-15}$	$\boxed{-18}$	…	$\boxed{-3n}$

Given:

Input	$1$	$2$	$3$	$4$	$5$	$6$	…	$n$
Output	$-3$	$-6$	$-9$	$-12$	$\boxed{}$	$\boxed{}$	…	$\boxed{}$

Calculation:

Input	$1$	$2$	$3$	$4$	$5$	$6$	…	$n$
Output	$-3$	$-6$	$-9$	$-12$	$\boxed{}$	$\boxed{}$	…	$\boxed{}$

For input $1$ :

  $\begin{array}{l}\text{Output}=-3\left(1\right)\\ \text{Output}=-3\end{array}$

For input $2$ :

  $\begin{array}{l}\text{Output}=-3\left(2\right)\\ \text{Output}=6\end{array}$

For input $3$ :

  $\begin{array}{l}\text{Output}=-3\left(3\right)\\ \text{Output}=-9\end{array}$

For input $4$ :

  $\begin{array}{l}\text{Output}=-3\left(4\right)\\ \text{Output}=-12\end{array}$

For input $5$ :

  $\begin{array}{l}\text{Output}=-3\left(5\right)\\ \text{Output}=-15\end{array}$

For input $6$ :

  $\begin{array}{l}\text{Output}=-3\left(6\right)\\ \text{Output}=-18\end{array}$

For input $n$ :

  $\begin{array}{l}\text{Output}=-3\left(n\right)\\ \text{Output}=-3n\end{array}$

Therefore, the table is:

Input	$1$	$2$	$3$	$4$	$5$	$6$	…	$n$
Output	$-3$	$-6$	$-9$	$-12$	$\boxed{-15}$	$\boxed{-18}$	…	$\boxed{-3n}$