Chapter 13, Problem 13E.1AE

(i)

Interpretation Introduction

Interpretation:

The constant volume molar heat capacity of ${\text{I}}_{\text{2}}$ in the gas phase at $2{\text{5 }}^{\text{ο}}\text{C}$ is to be calculated by using the equipartition theorem.

Concept introduction:

According to the equipartition theorem, the contribution of each degree of freedom to the heat capacity is $\frac{1}{2}R$.  The molar heat capacity at constant volume is calculated by using the formula shown below.

    $C_{V,m}=\text{translational}+\text{rotational}+\text{vibrational}$

(ii)

Interpretation Introduction

Interpretation:

The constant volume molar heat capacity of ${\text{CH}}_{\text{4}}$ in the gas phase at $2{\text{5 }}^{\text{ο}}\text{C}$ is to be calculated by using the equipartition theorem.

Concept introduction:

According to the equipartition theorem, the contribution of each degree of freedom to the heat capacity is $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.R$.  The molar heat capacity at constant volume is calculated by using the formula shown below.

    $C_{V,m}=\text{translational}+\text{rotational}+\text{vibrational}$

(iii)

Interpretation Introduction

Interpretation:

The constant volume molar heat capacity of ${\text{C}}_6{\text{H}}_6$ in the gas phase at $2{\text{5 }}^{\text{ο}}\text{C}$ is to be calculated by using the equipartition theorem.

Concept introduction:

According to the equipartition theorem, the contribution of each degree of freedom to the heat capacity is $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.R$.  The molar heat capacity at constant volume is calculated by using the formula shown below.

    $C_{V,m}=\text{translational}+\text{rotational}+\text{vibrational}$