Chapter 13, Problem 13.64P

Interpretation Introduction

Interpretation:

Pressure of $\text{45 g}$ of propane at $300°\text{C}$ in a $\text{2}\text{.2 L}$ container has to be calculated using ideal gas law and compared to pressure found from van der Waals equation.

Concept Introduction:

The combination of major gas laws namely Boyle’s law, Charles law and Avogadro’s leads to the ideal gas equation such as given below:

  $PV=nRT$

Here,

$R$ is the universal gas constant.

$V$ denotes the volume.

$n$ denotes the number of moles.

$T$ denotes temperature.

$P$ denotes the pressure.

Van der Waals equation is given as follows:

  $\left(P+\frac{a{n}^2}{V^2}\right)\left(V-nb\right)=nRT$

Here,

$a$ is a constant that gives the strength of the attractive force.

$b$ gives the measure of size of the gas molecules.