Chapter 13, Problem 13.56P

(a)

Interpretation Introduction

Interpretation:

The molarity of the aqueous solution of $32.3\text{g}$ of table sugar in $100\text{mL}$ of solution is to be determined.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by $M$ and its unit is $\text{mol/L}$.

The formula to calculate the molarity of the solution is as follows:

$\text{Molarity}=\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{volume }\left(\text{L}\right)\text{of}\text{}\text{solution}}$ (1)

(b)

Interpretation Introduction

Interpretation:

The molarity of the aqueous solution of $5.80\text{g}$ of ${\text{LiNO}}_3$ in $505\text{mL}$ of solution is to be determined.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by $M$ and its unit is $\text{mol/L}$.

The formula to calculate the molarity of the solution is as follows:

$\text{Molarity}=\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{volume }\left(\text{L}\right)\text{of}\text{}\text{solution}}$ (1)