Van’t Hoff factor and the information it provides has to be explained. Concept introduction Vant’t Hoff factor is derived from osmotic pressure. Osmotic pressure is the pressure that is needed to stop osmosis. Osmotic pressure of the solution is directly proportional to the concentration of the solution. We can calculate osmotic pressure by using this formula is given by, Osmotic pressure (π) = iMRT Where, i- Von’t Hoff’s factor M – Molarity of the solution (mol/L) R- Ideal gas constant (0.08206 L atm mol -1 K -1 ) T-Temperature in Kelvin Van’t Hoff factor is the ratio between actual colligative property of the particle and expected colligative property of the particle.

Question

Want to see the full answer?

Answer 1

Question

Chapter 13, Problem 13.54QP

Interpretation Introduction

Interpretation: Van’t Hoff factor and the information it provides has to be explained.

Concept introduction

Vant’t Hoff factor is derived from osmotic pressure. Osmotic pressure is the pressure that is needed to stop osmosis. Osmotic pressure of the solution is directly proportional to the concentration of the solution. We can calculate osmotic pressure by using this formula is given by,

Osmotic pressure (π) = iMRT

Where,

i- Von’t Hoff’s factor

M – Molarity of the solution (mol/L)

R- Ideal gas constant (0.08206 L atm mol-1K-1 )

T-Temperature in Kelvin

Van’t Hoff factor is the ratio between actual colligative property of the particle and expected colligative property of the particle.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Draw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl Substitution will not occur at a significant rate. Explanation Check :☐ O-CH + Х Click and drag to start drawing a structure.

Draw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl C O Substitution will not occur at a significant rate. Explanation Check + O-CH3 Х Click and drag to start drawing a structure.

✓ aw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. C Cl HO–CH O Substitution will not occur at a significant rate. Explanation Check -3 ☐ : + D Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Ce