Chapter 13, Problem 133QP

Interpretation Introduction

Interpretation:

The $\text{pH}$ of water at $60°\text{C}$ is to be determined.

Concept Introduction

The ionic product of water at the given temperature is calculated as shown in equation (1).

$K_w=\left[{\text{H}}^{+}\right]\left[{\text{OH}}^{-}\right]$ …(1)

Where $K_w,\left[{\text{H}}^{+}\right]$ , and $\left[{\text{OH}}^{-}\right]$ are the ionic product of water, hydrogen ion concentration, and hydroxyl ion concentration.

The $\text{pH}$ for the given solution is calculated as shown in equation (2).

$\text{pH}=\log \left[{\text{H}}^{+}\right]$ …(2)