The structure for the given spectrum is to be determined. Concept introduction: NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

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Answer 1

Question

Chapter 13, Problem 13.38SP

(a)

Interpretation Introduction

Interpretation:

The structure for the given spectrum is to be determined.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

(b)

Interpretation Introduction

Interpretation:

The appropriate peaks to show which protons give rise to which signals in the spectrum are to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

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A J то گای ه +0 Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01 number of moles= 0.400/277.15 = 0.00144 moles 2 x 0.00 144=0.00288 moves arams of acetophenone = 0.00144 X 120.16 = 0.1739 0.1739x2=0.3469 grams of benzaldehyde = 0.00144X106.12=0.1539 0.1539x2 = 0.3069 Starting materials: 0.3469 Ox acetophenone, 0.3069 of benzaldehyde 3

1. Answer the questions about the following reaction: (a) Draw in the arrows that can be used make this reaction occur and draw in the product of substitution in this reaction. Be sure to include any relevant stereochemistry in the product structure. + SK F Br + (b) In which solvent would this reaction proceed the fastest (Circle one) Methanol Acetone (c) Imagine that you are working for a chemical company and it was your job to perform a similar reaction to the one above, with the exception of the S atom in this reaction being replaced by an O atom. During the reaction, you observe the formation of three separate molecules instead of the single molecule obtained above. What is the likeliest other products that are formed? Draw them in the box provided.

Answer 2

Question

Chapter 13, Problem 13.38SP

(a)

Interpretation Introduction

Interpretation:

The structure for the given spectrum is to be determined.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

(b)

Interpretation Introduction

Interpretation:

The appropriate peaks to show which protons give rise to which signals in the spectrum are to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

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Answer 3

Question

Chapter 13, Problem 13.38SP

(a)

Interpretation Introduction

Interpretation:

The structure for the given spectrum is to be determined.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

(b)

Interpretation Introduction

Interpretation:

The appropriate peaks to show which protons give rise to which signals in the spectrum are to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

Expert Solution & Answer

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Answer 4

Question

Chapter 13, Problem 13.38SP

(a)

Interpretation Introduction

Interpretation:

The structure for the given spectrum is to be determined.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

(b)

Interpretation Introduction

Interpretation:

The appropriate peaks to show which protons give rise to which signals in the spectrum are to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

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Answer 5

Chapter 13, Problem 13.38SP

(a)

Interpretation Introduction

Interpretation:

The structure for the given spectrum is to be determined.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

(b)

Interpretation Introduction

Interpretation:

The appropriate peaks to show which protons give rise to which signals in the spectrum are to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

Answer 6

Chapter 13, Problem 13.38SP

(a)

Interpretation Introduction

Interpretation:

The structure for the given spectrum is to be determined.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

Answer 7

Chapter 13, Problem 13.38SP

(a)

Interpretation Introduction

Interpretation:

The structure for the given spectrum is to be determined.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The appropriate peaks to show which protons give rise to which signals in the spectrum are to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The appropriate peaks to show which protons give rise to which signals in the spectrum are to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

Answer 10

Expert Solution & Answer

Answer 11

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Answer 12

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Answer 13

Ch. 13.5A - In a 300-MHz spectrometer, the protons in...Ch. 13.5B - Prob. 13.2P Ch. 13.6 - Determine the number of different kinds of protons...Ch. 13.6 - Prob. 13.4P Ch. 13.7 - Draw the integral trace expected for the NMR...Ch. 13.7 - Prob. 13.6P Ch. 13.8C - Draw the NMR spectra you would expect for the...Ch. 13.8D - Draw the NMR spectra you expect for the following...Ch. 13.8D - a. Assign protons to the peaks in the NMR spectrum...Ch. 13.8D - Prob. 13.10P

The structure for the given spectrum is to be determined. Concept introduction: NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.

Solution Summary: The author explains NMR spectroscopy as a technique used to determine the carbon-hydrogen bonding of an organic compound.

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