
(a)
Interpretation:
It is to be shown how a retrosynthetic analysis might be constructed for the given synthesis.
Concept introduction:
Retrosynthesis is the planning of

Answer to Problem 13.30P
The retrosynthesis for the given synthesis is
Explanation of Solution
The given synthetic reaction is
In the given synthesis, the product differs from the starting compound by one ethyl group bonded to six-membered ring. Thus, the bond between the ethyl group and ring carbon in the target must break to transform it to the starting compound.
Therefore, retrosynthesis for the given synthetic reaction is
The retrosynthesis for the given synthetic reaction is shown by disconnecting the ethyl group from the ring.
(b)
Interpretation:
It is to be shown how a retrosynthetic analysis might be constructed for the given synthesis.
Concept introduction:
Retrosynthesis is the planning of organic synthesis, working backwards from target molecule to a simpler precursor, regardless of any interaction with reagents. Thus, the basis of retrosynthetic analysis is the transform, which means the reverse of a synthetic reaction. The precursors are the compounds, which are either readily available or easy to produce. The transform is indicated by an open arrow

Answer to Problem 13.30P
The retrosynthesis for the given synthesis is
Explanation of Solution
The given synthetic reaction is
The given synthesis is of two steps; the final product is the target molecule. Thus, retrosynthesis could be planned from the target to the intermediate product to the starting material. The target molecule and the intermediate product differ in bromine and cyanide. Thus, the bond between the cyanide and ring carbon must break to transform into an intermediate. The intermediate and the starting molecule differ by bromine atom. Thus, the bond between the bromine and ring carbon must break to transform into the starting material.
Therefore, the retrosynthesis for the given synthetic reaction is
The retrosynthesis for the given synthetic reaction is shown by disconnecting the cyanide group and then by disconnecting the bromine atom from the ring.
(c)
Interpretation:
It is to be shown how a retrosynthetic analysis might be constructed for the given synthesis.
Concept introduction:
Retrosynthesis is the planning of organic synthesis, working backwards from target molecule to a simpler precursor, regardless of any interaction with reagents. Thus, the basis of retrosynthetic analysis is the transform, which means the reverse of a synthetic reaction. The precursors are the compounds, which are either readily available or easy to produce. The transform is indicated by an open arrow

Answer to Problem 13.30P
The retrosynthesis for the given synthesis is
Explanation of Solution
The given synthetic reaction is
The given synthesis is of two steps; the final product is the target molecule. Thu, s the retrosynthesis could be planned from the target to the intermediate product to the starting material. The target molecule and the intermediate product differ in the benzyl group attached to the triple bonded carbon. Thus, the bond between the benzylic carbon and triple bonded carbon must break to transform into an intermediate. The intermediate can be transformed into the starting material by replacing the methyl group bonded to the oxygen atom by hydrogen.
Therefore, the retrosynthesis for the given synthetic reaction is
The retrosynthesis for the given synthetic reaction is shown by disconnecting the benzyl group from the triple bonded carbon and then by disconnecting the methyl group from the oxygen atom.
(d)
Interpretation:
It is to be shown how a retrosynthetic analysis might be constructed for the given synthesis.
Concept introduction:
Retrosynthesis is the planning of organic synthesis, working backwards from target molecule to a simpler precursor, regardless of any interaction with reagents. Thus, the basis of retrosynthetic analysis is the transform, which means the reverse of a synthetic reaction. The precursors are the compounds, which are either readily available or easy to produce. The transform is indicated by an open arrow

Answer to Problem 13.30P
The retrosynthesis for the given synthesis is
Explanation of Solution
The given synthetic reaction is
The given synthesis is of two steps; the final product is the target molecule. Thus the retrosynthesis could be planned from the target to the intermediate product to the starting material. The target molecule has a double bond, which is removed in the intermediate product having the ydroxyl group at that position. Thus, the
Therefore, the retrosynthesis for the given synthetic reaction is
The retrosynthesis for the given synthetic reaction is shown by disconnecting the
(e)
Interpretation:
It is to be shown how a retrosynthetic analysis might be constructed for the given synthesis.
Concept introduction:
Retrosynthesis is the planning of organic synthesis, working backwards from target molecule to a simpler precursor, regardless of any interaction with reagents. Thus, the basis of retrosynthetic analysis is the transform, which means the reverse of a synthetic reaction. The precursors are the compounds, which are either readily available or easy to produce. The transform is indicated by an open arrow

Answer to Problem 13.30P
The retrosynthesis for the given synthesis is
Explanation of Solution
The given synthetic reaction is
The given synthesis is of three steps; the final product is the target molecule. Thus, the retrosynthesis could be planned from the target to the second intermediate, then to the first intermediate, and finally into the starting material. The target molecule has the acetate group at the alpha position and the second intermediate has the bromine atom; thus, the bond between the alpha carbon and the oxygen of the acetate group must break. The second intermediate can be transformed into the first intermediate by breaking the bond between bromine and the alpha carbon. The first intermediate and the starting molecule differ by an additional methyl group; thus the bond between the alpha carbon and methyl must break to show the transform.
Therefore, the retrosynthesis for the given synthetic reaction is
The retrosynthesis for the given synthetic reaction is shown by disconnecting appropriate bonds.
(g)
Interpretation:
It is to be shown how a retrosynthetic analysis might be constructed for the given synthesis.
Concept introduction:
Retrosynthesis is the planning of organic synthesis, working backwards from target molecule to a simpler precursor, regardless of any interaction with reagents. Thus, the basis of retrosynthetic analysis is the transform, which means the reverse of a synthetic reaction. The precursors are the compounds, which are either readily available or easy to produce. The transform is indicated by an open arrow

Answer to Problem 13.30P
The retrosynthesis for the given synthesis is
Explanation of Solution
The given synthetic reaction is
The given synthesis is of three steps; the final product is the target molecule. Thus; the retrosynthesis could be planned from the target to the second intermediate; then to the first intermediate; and finally into the starting material. The target can be transformed to the second intermediate by replacing the nitride group by bromine; thus the bond between the nitride group and carbon must break. The second intermediate can be transformed into the first intermediate by replacing the bromine by hydroxyl group; thus the bond between bromine and carbon must break. The first intermediate can be transformed into the starting material by replacing the hydroxyl group by ethoxy group.
Therefore, the retrosynthesis for the given synthetic reaction is
The retrosynthesis for the given synthetic reaction is shown by disconnecting appropriate bonds.
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Chapter 13 Solutions
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
- Q6: Predict the major product(s) for the following reactions. Note the mechanism (SN1, SN2, E1 or E2) the reaction proceeds through. If no reaction takes place, indicate why. Pay attention to stereochemistry. NaCN DMF Br σ Ilm... Br H Br H H NaCN CH3OH KOtBu tBuOH NaBr H₂O LDA Et2O (CH3)2CHOH KCN DMSO NaOH H₂O, A LDA LDA Systemarrow_forwardQ7: For the following reactions, indicate the reaction conditions that would provide the indicated product in a high yield. Note the major reaction pathway that would take place (SN1, SN2, E1, or E2) Note: There may be other products that are not shown. There maybe more than one plausible pathway. Br H3C OH H3C CI ... H3C SCH2CH3 CI i SCH2CH3 ཨ་ Br System Settarrow_forwardQ2: Rank the compounds in each of the following groups in order of decreasing rate of solvolysis in aqueous acetone. OSO2CF3 OSO2CH3 OH a. b. CI Brarrow_forward
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- Please help me calculate the undiluted samples ppm concentration. My calculations were 280.11 ppm. Please see if I did my math correctly using the following standard curve. Link: https://mnscu-my.sharepoint.com/:x:/g/personal/vi2163ss_go_minnstate_edu/EVSJL_W0qrxMkUjK2J3xMUEBHDu0UM1vPKQ-bc9HTcYXDQ?e=hVuPC4arrow_forwardProvide an IUPAC name for each of the compounds shown. (Specify (E)/(Z) stereochemistry, if relevant, for straight chain alkenes only. Pay attention to commas, dashes, etc.) H₁₂C C(CH3)3 C=C H3C CH3 CH3CH2CH CI CH3 Submit Answer Retry Entire Group 2 more group attempts remaining Previous Nextarrow_forwardArrange the following compounds / ions in increasing nucleophilicity (least to most nucleophilic) CH3NH2 CH3C=C: CH3COO 1 2 3 5 Multiple Choice 1 point 1, 2, 3 2, 1, 3 3, 1, 2 2, 3, 1 The other answers are not correct 0000arrow_forward
- curved arrows are used to illustrate the flow of electrons. using the provided starting and product structures, draw the cured electron-pushing arrows for thw following reaction or mechanistic steps. be sure to account for all bond-breaking and bond making stepsarrow_forwardUsing the graphs could you help me explain the answers. I assumed that both graphs are proportional to the inverse of time, I think. Could you please help me.arrow_forwardSynthesis of Dibenzalacetone [References] Draw structures for the carbonyl electrophile and enolate nucleophile that react to give the enone below. Question 1 1 pt Question 2 1 pt Question 3 1 pt H Question 4 1 pt Question 5 1 pt Question 6 1 pt Question 7 1pt Question 8 1 pt Progress: 7/8 items Que Feb 24 at You do not have to consider stereochemistry. . Draw the enolate ion in its carbanion form. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. ⚫ Separate multiple reactants using the + sign from the drop-down menu. ? 4arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
