Chapter 13, Problem 13.154P

(a)

Interpretation Introduction

Interpretation:

The mass of glucose is to be calculated.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by $M$ and its unit is $\text{mol/L}$.

The formula to calculate the molarity of the solution is as follows:

  $\text{Molarity}\left(M\right)=\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{volume }\left(\text{L}\right)\text{of}\text{}\text{solution}}$        (1)

(b)

Interpretation Introduction

Interpretation:

The molarity of isotonic saline is to be calculated.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by $M$ and its unit is $\text{mol/L}$.

Tonicity is defined as the relative concentration of solutes dissolved in the solution that determines the direction and the extent of flow of particles. Two solutions are said to be isotonic if they have the same concentration.

(c)

Interpretation Introduction

Interpretation:

The mass of $\text{NaCl}$ is to be calculated.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by $M$ and its unit is $\text{mol/L}$.

The formula to calculate the molarity of the solution is as follows:

  $\text{Molarity}\left(M\right)=\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{volume }\left(\text{L}\right)\text{of}\text{}\text{solution}}$        (1)