CHEMISTRY W/WRKBK AND SMARTWORK (LL)
CHEMISTRY W/WRKBK AND SMARTWORK (LL)
5th Edition
ISBN: 9780393693447
Author: Gilbert
Publisher: NORTON
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Chapter 13, Problem 13.12VP

(a)

Interpretation Introduction

Interpretation: An image representing various reactions is given. Various questions based on the given image are to be answered.

Concept introduction: According to the collision theory, for a reaction to take place the molecules must collide in proper orientation and must have minimum energy so that the effective collisions may occur.

To determine: The two images that describe the elementary steps which when combined depicts the destruction of Ozone by Chlorine.

(a)

Expert Solution
Check Mark

Answer to Problem 13.12VP

Solution

The two images that describe the elementary steps which when combined depicts the destruction of Ozone by Chlorine are given by figure A and H.

Explanation of Solution

Explanation

The equation for the destruction of Ozone by Chlorine is given as,

O3(g)+Cl(g)ClO(g)+O2(g) (1)

O3(g)+ClO(g)Cl(g)+2O2(g) (2)

The equation (1) is represented by the figure A as shown,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 13, Problem 13.12VP , additional homework tip  1

As three red balls correspond to O3 while one green ball correspond to Cl . The equation (2) is represented by figure H as shown,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 13, Problem 13.12VP , additional homework tip  2

As three red balls correspond to O3 and one combined red and green ball correspond to ClO and one green ball correspond to Cl and each of two combined red balls represent one molecule of Oxygen.

Conclusion

The two images that describe the elementary steps which when combined depicts the destruction of Ozone by Chlorine are given by figure A and H.

(b)

Interpretation Introduction

Interpretation: An image representing various reactions is given. Various questions based on the given image are to be answered.

Concept introduction: According to the collision theory, for a reaction to take place the molecules must collide in proper orientation and must have minimum energy so that the effective collisions may occur.

To determine: The image that represents the overall reaction for the Chlorine catalyzed destruction of Ozone.

(b)

Expert Solution
Check Mark

Answer to Problem 13.12VP

Solution

The image that represents the overall reaction for the Chlorine catalyzed destruction of Ozone is given by figure E.

Explanation of Solution

Explanation

The equation for the destruction of Ozone by Chlorine is given as,

O3(g)+Cl(g)ClO(g)+O2(g) (1)

O3(g)+ClO(g)Cl(g)+2O2(g) (2)

The overall reaction is given as,

2O3(g)3O2(g)

This situation is represented by figure E as shown below,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 13, Problem 13.12VP , additional homework tip  3

As three red balls combined in reactants correspond to O3 while 3 images of combined two red balls correspond to O2 .

Conclusion

The image that represents the overall reaction for the Chlorine catalyzed destruction of Ozone is given by figure E.

(c)

Interpretation Introduction

Interpretation: An image representing various reactions is given. Various questions based on the given image are to be answered.

Concept introduction: According to the collision theory, for a reaction to take place the molecules must collide in proper orientation and must have minimum energy so that the effective collisions may occur.

To determine: The two images that describe the elementary steps which when combined describes the overall reaction in which NO3 acts as an intermediate.

(c)

Expert Solution
Check Mark

Answer to Problem 13.12VP

Solution

The two images that describe the elementary steps which when combined describe the overall reaction in which NO3 acts as an intermediate are figure D and B.

Explanation of Solution

Explanation

The reaction involving NO3 as an intermediate is given as,

NO2(g)+NO2(g)NO3(g)+NO(g) (3)

NO3(g)+CO(g)NO2(g)+CO2(g) (4)

The equation (3) is represented by figure D as shown below,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 13, Problem 13.12VP , additional homework tip  4

Here, a pair of combined red and blue balls corresponds to NO2 and three combined red balls along with one blue ball corresponds to NO3 and one combined red and blue ball correspond to NO . The equation (4) is represented by figure B as shown below,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 13, Problem 13.12VP , additional homework tip  5

Here, three combined red balls along with one blue ball corresponds to NO3 and combined one red and black ball correspond to CO while at the right hand side, combined two red and one blue ball correspond to NO2 and combined two red and one black ball correspond to CO2 .

Conclusion

The two images that describe the elementary steps which when combined describe the overall reaction in which NO3 acts as an intermediate are figure D and B.

(d)

Interpretation Introduction

Interpretation: An image representing various reactions is given. Various questions based on the given image are to be answered.

Concept introduction: According to the collision theory, for a reaction to take place the molecules must collide in proper orientation and must have minimum energy so that the effective collisions may occur.

To determine: The chemical equation for the reaction described in question (c).

(d)

Expert Solution
Check Mark

Answer to Problem 13.12VP

Solution

The chemical equation for the reaction described in question (c) is,

NO2(g)+CO(g)CO2(g)+NO(g)

Explanation of Solution

Explanation

The reaction involving NO3 as an intermediate is given as,

NO2(g)+NO2(g)NO3(g)+NO(g) (3)

NO3(g)+CO(g)NO2(g)+CO2(g) (4)

The chemical equation for the overall reaction is given by adding equation (3) and (4) as,

NO2(g)+CO(g)CO2(g)+NO(g)

Conclusion

The chemical equation for the reaction described in question (c) is,

NO2(g)+CO(g)CO2(g)+NO(g)

(e)

Interpretation Introduction

Interpretation: An image representing various reactions is given. Various questions based on the given image are to be answered.

Concept introduction: According to the collision theory, for a reaction to take place the molecules must collide in proper orientation and must have minimum energy so that the effective collisions may occur.

To determine: The image that shows photodecomposition of Chlorofluorocarbons.

(e)

Expert Solution
Check Mark

Answer to Problem 13.12VP

Solution

The image that shows photodecomposition of Chlorofluorocarbons is given by figure G.

Explanation of Solution

Explanation

The decomposition of Chlorofluorocarbons is given as,

CF4hνCF3·+F·

This equation is represented by figure G as shown below.

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 13, Problem 13.12VP , additional homework tip  6

As four combined green and one black ball at left hand side corresponds to CF4 while combined three green and one black ball and one single green ball correspond to CF3· and F· respectively.

Conclusion

The image that shows photodecomposition of Chlorofluorocarbons is given by figure G.

(f)

Interpretation Introduction

Interpretation: An image representing various reactions is given. Various questions based on the given image are to be answered.

Concept introduction: According to the collision theory, for a reaction to take place the molecules must collide in proper orientation and must have minimum energy so that the effective collisions may occur.

To determine: The decreasing order for the collision between Ozone and chlorine atoms.

(f)

Expert Solution
Check Mark

Answer to Problem 13.12VP

Solution

The decreasing order for the collision between Ozone and chlorine atoms is I>F>C .

Explanation of Solution

Explanation

The absence of Ozone is represented by the blue cloud. The cloud is bigger in figure I, it means Ozone is most depleted in figure I and it corresponds to the maximum number of collisions between Ozone and Chlorine atoms as shown below,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 13, Problem 13.12VP , additional homework tip  7

Then figure F shows the less depletion of Ozone in comparison to figure I as shown below,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 13, Problem 13.12VP , additional homework tip  8

The least depletion of Ozone is shown in figure C as shown below,

CHEMISTRY W/WRKBK AND SMARTWORK (LL), Chapter 13, Problem 13.12VP , additional homework tip  9

Therefore, the decreasing number of collisions is given by I>F>C .

Conclusion

The decreasing order for the collision between Ozone and chlorine atoms is I>F>C .

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Chapter 13 Solutions

CHEMISTRY W/WRKBK AND SMARTWORK (LL)

Ch. 13.5 - Prob. 11PECh. 13.5 - Prob. 12PECh. 13.6 - Prob. 13PECh. 13 - Prob. 13.1VPCh. 13 - Prob. 13.2VPCh. 13 - Prob. 13.3VPCh. 13 - Prob. 13.4VPCh. 13 - Prob. 13.5VPCh. 13 - Prob. 13.6VPCh. 13 - Prob. 13.7VPCh. 13 - Prob. 13.8VPCh. 13 - Prob. 13.9VPCh. 13 - Prob. 13.10VPCh. 13 - Prob. 13.11VPCh. 13 - Prob. 13.12VPCh. 13 - Prob. 13.13QPCh. 13 - Prob. 13.14QPCh. 13 - Prob. 13.15QPCh. 13 - Prob. 13.16QPCh. 13 - Prob. 13.17QPCh. 13 - Prob. 13.18QPCh. 13 - Prob. 13.19QPCh. 13 - Prob. 13.20QPCh. 13 - Prob. 13.21QPCh. 13 - Prob. 13.22QPCh. 13 - Prob. 13.23QPCh. 13 - Prob. 13.24QPCh. 13 - Prob. 13.25QPCh. 13 - Prob. 13.26QPCh. 13 - Prob. 13.27QPCh. 13 - Prob. 13.28QPCh. 13 - Prob. 13.29QPCh. 13 - Prob. 13.30QPCh. 13 - Prob. 13.31QPCh. 13 - Prob. 13.32QPCh. 13 - Prob. 13.33QPCh. 13 - Prob. 13.34QPCh. 13 - Prob. 13.35QPCh. 13 - Prob. 13.36QPCh. 13 - Prob. 13.37QPCh. 13 - Prob. 13.38QPCh. 13 - Prob. 13.39QPCh. 13 - Prob. 13.40QPCh. 13 - Prob. 13.41QPCh. 13 - Prob. 13.42QPCh. 13 - Prob. 13.43QPCh. 13 - Prob. 13.44QPCh. 13 - Prob. 13.45QPCh. 13 - Prob. 13.46QPCh. 13 - Prob. 13.47QPCh. 13 - Prob. 13.48QPCh. 13 - Prob. 13.49QPCh. 13 - Prob. 13.50QPCh. 13 - Prob. 13.51QPCh. 13 - Prob. 13.52QPCh. 13 - Prob. 13.53QPCh. 13 - Prob. 13.54QPCh. 13 - Prob. 13.55QPCh. 13 - Prob. 13.56QPCh. 13 - Prob. 13.57QPCh. 13 - Prob. 13.58QPCh. 13 - Prob. 13.59QPCh. 13 - Prob. 13.60QPCh. 13 - Prob. 13.61QPCh. 13 - Prob. 13.62QPCh. 13 - Prob. 13.63QPCh. 13 - Prob. 13.64QPCh. 13 - Prob. 13.65QPCh. 13 - Prob. 13.66QPCh. 13 - Prob. 13.67QPCh. 13 - Prob. 13.68QPCh. 13 - Prob. 13.69QPCh. 13 - Prob. 13.70QPCh. 13 - Prob. 13.71QPCh. 13 - Prob. 13.72QPCh. 13 - Prob. 13.73QPCh. 13 - Prob. 13.74QPCh. 13 - Prob. 13.75QPCh. 13 - Prob. 13.76QPCh. 13 - Prob. 13.77QPCh. 13 - Prob. 13.78QPCh. 13 - Prob. 13.79QPCh. 13 - Prob. 13.80QPCh. 13 - Prob. 13.81QPCh. 13 - Prob. 13.82QPCh. 13 - Prob. 13.83QPCh. 13 - Prob. 13.84QPCh. 13 - Prob. 13.85QPCh. 13 - Prob. 13.86QPCh. 13 - Prob. 13.87QPCh. 13 - Prob. 13.88QPCh. 13 - Prob. 13.89QPCh. 13 - Prob. 13.90QPCh. 13 - Prob. 13.91QPCh. 13 - Prob. 13.92QPCh. 13 - Prob. 13.93QPCh. 13 - Prob. 13.94QPCh. 13 - Prob. 13.95QPCh. 13 - Prob. 13.96QPCh. 13 - Prob. 13.97QPCh. 13 - Prob. 13.98QPCh. 13 - Prob. 13.99QPCh. 13 - Prob. 13.100QPCh. 13 - Prob. 13.101QPCh. 13 - Prob. 13.102QPCh. 13 - Prob. 13.103QPCh. 13 - Prob. 13.104QPCh. 13 - Prob. 13.105QPCh. 13 - Prob. 13.106QPCh. 13 - Prob. 13.107QPCh. 13 - Prob. 13.108QPCh. 13 - Prob. 13.109QPCh. 13 - Prob. 13.110QPCh. 13 - Prob. 13.111QPCh. 13 - Prob. 13.112QPCh. 13 - Prob. 13.113QPCh. 13 - Prob. 13.114QPCh. 13 - Prob. 13.115QPCh. 13 - Prob. 13.116QPCh. 13 - Prob. 13.117APCh. 13 - Prob. 13.118APCh. 13 - Prob. 13.119APCh. 13 - Prob. 13.120APCh. 13 - Prob. 13.121APCh. 13 - Prob. 13.122APCh. 13 - Prob. 13.123APCh. 13 - Prob. 13.124APCh. 13 - Prob. 13.125APCh. 13 - Prob. 13.126APCh. 13 - Prob. 13.127APCh. 13 - Prob. 13.128APCh. 13 - Prob. 13.129APCh. 13 - Prob. 13.130AP
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