Physics
Physics
3rd Edition
ISBN: 9781259233616
Author: GIAMBATTISTA
Publisher: MCG
bartleby

Concept explainers

Question
Book Icon
Chapter 13, Problem 106P
To determine

The decrease in the rms speed of the air molecules in lungs.

Expert Solution & Answer
Check Mark

Answer to Problem 106P

The decrease in the rms speed of the air molecules in lungs is 25m/s.

Explanation of Solution

The temperature change of ground squirrel during hibernation is from 40.0°C to 10.0°C. The air in the lungs of the squirrel is composed of 75.0% nitrogen and 25.0% of oxygen.

Write the formula for the rms speed.

vrms=3kTm (I)

Here, vrms is the rms speed, k is the Boltzmann’s constant, T is the temperature, m is the mass.

Refer equation (I) and write an equation for the change in rms speed.

Δvrms=3kTfm3kTim (II)

Here, Δvrms is the change in rms speed, Tf is the final temperature, Ti is the initial temperature.

Write the formula for the mass of air.

M=(0.75)(2×MN)+(0.25)(2×MO) (III)

Here, MN is the molar mass of nitrogen, MO is the molar mass of oxygen.

Substitute equation (III) in equation (II).Δvrms=3kTf(0.75)(2×MN)+(0.25)(2×MO)3kTi(0.75)(2×MN)+(0.25)(2×MO) (IV)

Conclusion:

Substitute 1.38×1023J/K for k, 40.0°C for Ti, 10.0°C for Tf, 14.0067u for MN, 15.9994u for MO.

Δvrms={3(1.38×1023J/K)(10.0°C)(0.75)(2×14.0067u)+(0.25)(2×15.9994u)3(1.38×1023J/K)(40.0°C)(0.75)(2×14.0067u)+(0.25)(2×15.9994u)}={3(1.38×1023J/K)(10.0+273K)[(0.75)(2×14.0067u)+(0.25)(2×15.9994u)](1.66×1027kg/u)3(1.38×1023J/K)(40.0+273K)(0.75)(2×14.0067u)+(0.25)(2×15.9994u)(1.66×1027kg/u)}=493m/s518m/s=25m/s

The decrease in the rms speed of the air molecules in lungs is 25m/s.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Describe how the momentum of a single ball changes as it free falls from a height of approximately 1 m, collides with a hard floor, and rebounds.
• Nature of Resistance Temperature-Resistance Relationship Ohm's Law, Energy and Power Kirchhoff's Law • • Maxwell's Mesh Analysis 1. The steel of the third rail of a railway system has a resistivity of 21.4 μ-cm. If its cross-sectional area is 8.2 in², calculate the resistance per mile of rail, neglecting the effect of joints between sections. (1 point) 2. An incandescent lamp has a tungsten filament whose resistance is 96 at its operating temperature of 2900°C. Calculate the filament resistance when the lamp is disconnected from the electric source, under which condition its temperature is 24°C. (Use do = 0.0045 02/°C for tungsten) (1 point) 3. For the circuit shown, find the following: 50 V 602 10 V 702 a. the value of resistor R. (1 point) b. the equivalent resistance with respect to the 50-V source. (1 point) 4. For the circuit shown, determine all the currents in each branch using Kirchhoff's Laws. (3 points) A 5V 2 В -ний C 4 6 VT ww F E 5. Use Maxwell's Mesh to find I, and VAB…
For items 8-9, refer to the problem below. Find all the currents flowing in every resistor, power dissipation in every resistor and the total power of the circuit shown at the right using... 8. Kirchhoff's Laws (5 pts) 9. Maxwell's Mesh Analysis (5 pts) A 8 V 10 V B + 20 Ω 3Ω 202 wwww C wwww 202 + 50 www 12 V

Chapter 13 Solutions

Physics

Ch. 13.6 - Prob. 13.7PPCh. 13.7 - Prob. 13.8PPCh. 13.8 - Prob. 13.9PPCh. 13 - Prob. 1CQCh. 13 - Prob. 2CQCh. 13 - Prob. 3CQCh. 13 - Prob. 4CQCh. 13 - Prob. 5CQCh. 13 - Prob. 6CQCh. 13 - Prob. 7CQCh. 13 - Prob. 8CQCh. 13 - Prob. 9CQCh. 13 - Prob. 10CQCh. 13 - Prob. 11CQCh. 13 - Prob. 12CQCh. 13 - Prob. 13CQCh. 13 - Prob. 14CQCh. 13 - Prob. 15CQCh. 13 - Prob. 16CQCh. 13 - Prob. 17CQCh. 13 - Prob. 18CQCh. 13 - Prob. 19CQCh. 13 - Prob. 20CQCh. 13 - Prob. 1MCQCh. 13 - Prob. 2MCQCh. 13 - Prob. 3MCQCh. 13 - Prob. 4MCQCh. 13 - Prob. 5MCQCh. 13 - Prob. 6MCQCh. 13 - Prob. 7MCQCh. 13 - Prob. 8MCQCh. 13 - Prob. 9MCQCh. 13 - Prob. 10MCQCh. 13 - Prob. 1PCh. 13 - Prob. 2PCh. 13 - Prob. 3PCh. 13 - Prob. 4PCh. 13 - Prob. 5PCh. 13 - Prob. 6PCh. 13 - Prob. 7PCh. 13 - Prob. 8PCh. 13 - Prob. 9PCh. 13 - Prob. 10PCh. 13 - Prob. 11PCh. 13 - Prob. 12PCh. 13 - Prob. 13PCh. 13 - Prob. 14PCh. 13 - Prob. 15PCh. 13 - Prob. 16PCh. 13 - Prob. 17PCh. 13 - Prob. 18PCh. 13 - Prob. 19PCh. 13 - Prob. 20PCh. 13 - Prob. 21PCh. 13 - 22. A copper washer is to be fit in place over a...Ch. 13 - 23. Repeat Problem 22, but now the copper washer...Ch. 13 - Prob. 24PCh. 13 - Prob. 25PCh. 13 - Prob. 26PCh. 13 - Prob. 27PCh. 13 - Prob. 28PCh. 13 - Prob. 29PCh. 13 - Prob. 30PCh. 13 - Prob. 31PCh. 13 - Prob. 32PCh. 13 - Prob. 33PCh. 13 - Prob. 34PCh. 13 - Prob. 35PCh. 13 - Prob. 36PCh. 13 - Prob. 37PCh. 13 - Prob. 38PCh. 13 - Prob. 39PCh. 13 - Prob. 40PCh. 13 - Prob. 41PCh. 13 - Prob. 42PCh. 13 - Prob. 43PCh. 13 - Prob. 44PCh. 13 - Prob. 45PCh. 13 - Prob. 46PCh. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Prob. 49PCh. 13 - Prob. 50PCh. 13 - Prob. 51PCh. 13 - Prob. 52PCh. 13 - Prob. 53PCh. 13 - Prob. 54PCh. 13 - Prob. 55PCh. 13 - Prob. 56PCh. 13 - Prob. 57PCh. 13 - Prob. 58PCh. 13 - Prob. 59PCh. 13 - Prob. 60PCh. 13 - Prob. 61PCh. 13 - Prob. 62PCh. 13 - Prob. 63PCh. 13 - Prob. 64PCh. 13 - Prob. 65PCh. 13 - Prob. 66PCh. 13 - Prob. 67PCh. 13 - Prob. 68PCh. 13 - Prob. 69PCh. 13 - Prob. 70PCh. 13 - Prob. 71PCh. 13 - Prob. 72PCh. 13 - Prob. 73PCh. 13 - Prob. 74PCh. 13 - Prob. 75PCh. 13 - Prob. 76PCh. 13 - Prob. 77PCh. 13 - Prob. 78PCh. 13 - Prob. 79PCh. 13 - Prob. 80PCh. 13 - Prob. 81PCh. 13 - Prob. 82PCh. 13 - Prob. 83PCh. 13 - Prob. 84PCh. 13 - Prob. 85PCh. 13 - Prob. 86PCh. 13 - Prob. 87PCh. 13 - Prob. 88PCh. 13 - Prob. 89PCh. 13 - Prob. 90PCh. 13 - Prob. 91PCh. 13 - Prob. 92PCh. 13 - Prob. 93PCh. 13 - Prob. 94PCh. 13 - Prob. 95PCh. 13 - Prob. 96PCh. 13 - Prob. 97PCh. 13 - Prob. 98PCh. 13 - Prob. 99PCh. 13 - Prob. 100PCh. 13 - Prob. 101PCh. 13 - Prob. 102PCh. 13 - Prob. 103PCh. 13 - Prob. 104PCh. 13 - Prob. 105PCh. 13 - Prob. 106PCh. 13 - Prob. 107PCh. 13 - Prob. 108PCh. 13 - Prob. 109PCh. 13 - Prob. 110PCh. 13 - Prob. 111PCh. 13 - Prob. 112PCh. 13 - 113. A long, narrow steel rod of length 2.5000 m...Ch. 13 - Prob. 114PCh. 13 - Prob. 115PCh. 13 - Prob. 116PCh. 13 - Prob. 117PCh. 13 - Prob. 118PCh. 13 - Prob. 119PCh. 13 - Prob. 120P
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Text book image
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
Text book image
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON