ORGANIC CHEMISTRY W/ALEKS
ORGANIC CHEMISTRY W/ALEKS
6th Edition
ISBN: 9781264905430
Author: SMITH
Publisher: MCG CUSTOM
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Chapter 12C.8, Problem 21P

Identify A and B, isomers of molecular formula C 3 H 4 Cl 2 , from the given 1 H NMR data: Compound A exhibits signals at 1.75 ( doublet, 3H,  J = 6 .9 Hz ) and 5.89 ( quartet, 1H,  J = 6 .9 Hz ) ppm . Compound B exhibits signals at 4.16 ( singlet, 2H ) , 5.42 ( doublet, 1H,  J = 1. 9 Hz ) , and 5.59 ( doublet, 1H,  J = 1. 9 Hz ) ppm .

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Identify A and B, isomers of molecular formula C3H4Cl2, from the given 1H NMR data: Compound A exhibits peaks at 1.75 (doublet, 3 H, J = 6.9 Hz) and 5.89 (quartet, 1 H, J = 6.9 Hz) ppm. Compound B exhibits peaks at 4.16 (singlet, 2 H), 5.42 (doublet, 1 H, J = 1.9 Hz), and 5.59 (doublet, 1 H, J = 1.9 Hz) ppm.
Identify A and B, isomers of molecular formula C3H4Cl2, from the given 1H NMR data: Compound AJ = 6.9 Hz) and 5.89 (quartet, 1 H, J = 6.9 Hz) ppm. Compound B exhibits signals at 4.16 (singlet, 2 H), 5.42 (doublet, 1 H, J = 1.9 Hz), and 5.59 (doublet, 1 H, J = 1.9 Hz) ppm.
Compound A, with molecular formula C4H9Cl, shows two signals in its 13C NMR spectrum. Compound B, an isomer of compound A, shows foursignals, and in the proton-coupled mode, the signal farthest downfield is a doublet. Identify compounds A and B.

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ORGANIC CHEMISTRY W/ALEKS

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NMR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=SBir5wUS3Bo;License: Standard YouTube License, CC-BY