Explanation Given: Total 100 delegates are to be apportioned among three states A, B and C with populations 144, 443 and 389 respectively. Formula Used: Standard divisor = total population number of delegates Standard quota = state population standard divisor Calculations: Number of delegates to be apportioned = 100 Total population of the three states = 144 + 443 + 389 = 976 Calculate standard divisor Standard divisor = 976 100 = 9.76 Calculate Standard quota for each state Standard quota = state population 9.76 (These calculations are shown in the third row of the table below) Give each state the number of delegates found by rounding its standard quota down. This number is the state’s minimum quota. (These calculations are shown in the fourth row of the table below) Find the sum total of the delegates so obtained. You will find that two delegate are left to be apportioned. State A B C Total Population 144 443 389 986 Standard quota 144 9.76 = 14.75 443 9.76 = 45.39 389 9.76 = 39.86 100 Minimum quota 14 45 39 98 Part (a): Hamilton’s Method of apportionment Find each state’s fractional remainder – fraction that remains in the standard quota after subtracting the minimum quota. Give one of each extra delegate to the states with highest fractional remainder. (These calculations are shown in the fifth row of the table below) The final apportionment is given in the sixth row of the table below: State A B C Total Population 144 443 389 986 Standard quota 144 9.76 = 14.75 443 9.76 = 45.39 389 9.76 = 39.86 100 Minimum quota 14 45 39 98 Fractional remainder 0.75 (2 nd largest) 0.39 0.86 (largest) 2 Final Apportionment 15 45 40 100 Thus, the apportionment to the three states A, B and C are 15, 45 and 40 respectively. Part (b): Jefferson’s Method of apportionment Since, there are two extra seats, so according to this method you have to choose a modified divisor that is lower than the standard divisor. The state population is divided by modified divisor to find modified quota. Round these modified quotas to find new set of minimum quotas. The last row in the table below shows the new minimum quotas with a modified divisor of 9.61. Observe that this new set of minimum quota uses all 100 seats. Hence, the last row is the final apportionment. State A B C Total Population 144 443 389 986 Standard quota 144 9.76 = 14.75 443 9.76 = 45.39 389 9.76 = 39.86 100 Minimum quota 14 45 39 98 Modified quota 144 9.61 = 14.98 443 9.61 = 46.10 389 9.61 = 40.48 101...

6th Edition

ISBN: 8220100802713

Author: Briggs

Publisher: PEARSON

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Chapter 12.C, Problem 40E

To determine

There are five parts to be determined in this question and these are:

(a) To find apportionment using Hamilton’s method.

(b) To find apportionment using Jefferson’s method.

(c) To find apportionment using Webster’s method.

(d) To find apportionment using Hill-Huntington’s method.

(e) Compare results of various methods

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Chapter 12.C, Problem 39E

Chapter 12.C, Problem 41E

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