The specific heat ratio using molar analysis.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 12.9, Problem 1E

To determine

The specific heat ratio using molar analysis.

Expert Solution & Answer

Answer to Problem 1E

The specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Explanation of Solution

Write the expression to calculate the specific heat ratio of mixture km contains H2,O2 and CO using the following relation from molar analysis.

km=(cp)m(cv)m (I)

Here, the specific heat at constant pressure of the mixture is (cp)m, the specific heat at constant volume of the mixture is (cv)m.

Write the expression for specific heat at constant pressure of the mixture (cp)m.

(cp)m=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,CO (II)

Here, the mass fraction of hydrogen is mfH2, the mass fraction of oxygen is mfO2, the mass fraction of carbon monoxide is mfCO, the specific heat capacity at constant pressure of hydrogen at 300 K is cp,H2, the specific heat capacity at constant pressure of oxygen at 300 K is cp,O2, and the specific heat capacity at constant pressure of carbon monoxide at 300 K is cp,CO.

Write the expression for specific heat at constant volume of the mixture (cv)m.

(cv)m=mfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO (III)

Here, the specific heat capacity at constant volume of hydrogen at 300 K is cv,H2,the specific heat capacity at constant volume of oxygen at 300 K is cv,O2, specific heat capacity at constant volume of carbon monoxide at 300 K is cv,CO.

Conclusion:

Substitute Equation (II) and (III) in (I).

km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO

Thus, the specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

1.1 m 1.3 m B 60-mm diameter Brass 40-mm diameter Aluminum PROBLEM 2.52 - A rod consisting of two cylindrical portions AB and BC is restrained at both ends. Portion AB is made of brass (E₁ = 105 GPa, α = 20.9×10°/°C) and portion BC is made of aluminum (Ę₁ =72 GPa, α = 23.9×10/°C). Knowing that the rod is initially unstressed, determine (a) the normal stresses induced in portions AB and BC by a temperature rise of 42°C, (b) the corresponding deflection of point B.

30 mm D = 40 MPa -30 mm B C 80 MPa PROBLEM 2.69 A 30-mm square was scribed on the side of a large steel pressure vessel. After pressurization, the biaxial stress condition at the square is as shown. For E = 200 GPa and v=0.30, determine the change in length of (a) side AB, (b) side BC, (c) diagnonal AC.

Please solve in detail this problem thank you

Answer 2

Question

Chapter 12.9, Problem 1E

To determine

The specific heat ratio using molar analysis.

Expert Solution & Answer

Answer to Problem 1E

The specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Explanation of Solution

Write the expression to calculate the specific heat ratio of mixture km contains H2,O2 and CO using the following relation from molar analysis.

km=(cp)m(cv)m (I)

Here, the specific heat at constant pressure of the mixture is (cp)m, the specific heat at constant volume of the mixture is (cv)m.

Write the expression for specific heat at constant pressure of the mixture (cp)m.

(cp)m=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,CO (II)

Here, the mass fraction of hydrogen is mfH2, the mass fraction of oxygen is mfO2, the mass fraction of carbon monoxide is mfCO, the specific heat capacity at constant pressure of hydrogen at 300 K is cp,H2, the specific heat capacity at constant pressure of oxygen at 300 K is cp,O2, and the specific heat capacity at constant pressure of carbon monoxide at 300 K is cp,CO.

Write the expression for specific heat at constant volume of the mixture (cv)m.

(cv)m=mfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO (III)

Here, the specific heat capacity at constant volume of hydrogen at 300 K is cv,H2,the specific heat capacity at constant volume of oxygen at 300 K is cv,O2, specific heat capacity at constant volume of carbon monoxide at 300 K is cv,CO.

Conclusion:

Substitute Equation (II) and (III) in (I).

km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO

Thus, the specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 12.9, Problem 1E

To determine

The specific heat ratio using molar analysis.

Expert Solution & Answer

Answer to Problem 1E

The specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Explanation of Solution

Write the expression to calculate the specific heat ratio of mixture km contains H2,O2 and CO using the following relation from molar analysis.

km=(cp)m(cv)m (I)

Here, the specific heat at constant pressure of the mixture is (cp)m, the specific heat at constant volume of the mixture is (cv)m.

Write the expression for specific heat at constant pressure of the mixture (cp)m.

(cp)m=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,CO (II)

Here, the mass fraction of hydrogen is mfH2, the mass fraction of oxygen is mfO2, the mass fraction of carbon monoxide is mfCO, the specific heat capacity at constant pressure of hydrogen at 300 K is cp,H2, the specific heat capacity at constant pressure of oxygen at 300 K is cp,O2, and the specific heat capacity at constant pressure of carbon monoxide at 300 K is cp,CO.

Write the expression for specific heat at constant volume of the mixture (cv)m.

(cv)m=mfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO (III)

Here, the specific heat capacity at constant volume of hydrogen at 300 K is cv,H2,the specific heat capacity at constant volume of oxygen at 300 K is cv,O2, specific heat capacity at constant volume of carbon monoxide at 300 K is cv,CO.

Conclusion:

Substitute Equation (II) and (III) in (I).

km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO

Thus, the specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 12.9, Problem 1E

To determine

The specific heat ratio using molar analysis.

Expert Solution & Answer

Answer to Problem 1E

The specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Explanation of Solution

Write the expression to calculate the specific heat ratio of mixture km contains H2,O2 and CO using the following relation from molar analysis.

km=(cp)m(cv)m (I)

Here, the specific heat at constant pressure of the mixture is (cp)m, the specific heat at constant volume of the mixture is (cv)m.

Write the expression for specific heat at constant pressure of the mixture (cp)m.

(cp)m=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,CO (II)

Here, the mass fraction of hydrogen is mfH2, the mass fraction of oxygen is mfO2, the mass fraction of carbon monoxide is mfCO, the specific heat capacity at constant pressure of hydrogen at 300 K is cp,H2, the specific heat capacity at constant pressure of oxygen at 300 K is cp,O2, and the specific heat capacity at constant pressure of carbon monoxide at 300 K is cp,CO.

Write the expression for specific heat at constant volume of the mixture (cv)m.

(cv)m=mfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO (III)

Here, the specific heat capacity at constant volume of hydrogen at 300 K is cv,H2,the specific heat capacity at constant volume of oxygen at 300 K is cv,O2, specific heat capacity at constant volume of carbon monoxide at 300 K is cv,CO.

Conclusion:

Substitute Equation (II) and (III) in (I).

km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO

Thus, the specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 12.9, Problem 1E

To determine

The specific heat ratio using molar analysis.

Expert Solution & Answer

Answer to Problem 1E

The specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Explanation of Solution

Write the expression to calculate the specific heat ratio of mixture km contains H2,O2 and CO using the following relation from molar analysis.

km=(cp)m(cv)m (I)

Here, the specific heat at constant pressure of the mixture is (cp)m, the specific heat at constant volume of the mixture is (cv)m.

Write the expression for specific heat at constant pressure of the mixture (cp)m.

(cp)m=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,CO (II)

Here, the mass fraction of hydrogen is mfH2, the mass fraction of oxygen is mfO2, the mass fraction of carbon monoxide is mfCO, the specific heat capacity at constant pressure of hydrogen at 300 K is cp,H2, the specific heat capacity at constant pressure of oxygen at 300 K is cp,O2, and the specific heat capacity at constant pressure of carbon monoxide at 300 K is cp,CO.

Write the expression for specific heat at constant volume of the mixture (cv)m.

(cv)m=mfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO (III)

Here, the specific heat capacity at constant volume of hydrogen at 300 K is cv,H2,the specific heat capacity at constant volume of oxygen at 300 K is cv,O2, specific heat capacity at constant volume of carbon monoxide at 300 K is cv,CO.

Conclusion:

Substitute Equation (II) and (III) in (I).

km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO

Thus, the specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Answer 6

Chapter 12.9, Problem 1E

To determine

The specific heat ratio using molar analysis.

Expert Solution & Answer

Answer to Problem 1E

The specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Explanation of Solution

Write the expression to calculate the specific heat ratio of mixture km contains H2,O2 and CO using the following relation from molar analysis.

km=(cp)m(cv)m (I)

Here, the specific heat at constant pressure of the mixture is (cp)m, the specific heat at constant volume of the mixture is (cv)m.

Write the expression for specific heat at constant pressure of the mixture (cp)m.

(cp)m=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,CO (II)

Here, the mass fraction of hydrogen is mfH2, the mass fraction of oxygen is mfO2, the mass fraction of carbon monoxide is mfCO, the specific heat capacity at constant pressure of hydrogen at 300 K is cp,H2, the specific heat capacity at constant pressure of oxygen at 300 K is cp,O2, and the specific heat capacity at constant pressure of carbon monoxide at 300 K is cp,CO.

Write the expression for specific heat at constant volume of the mixture (cv)m.

(cv)m=mfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO (III)

Here, the specific heat capacity at constant volume of hydrogen at 300 K is cv,H2,the specific heat capacity at constant volume of oxygen at 300 K is cv,O2, specific heat capacity at constant volume of carbon monoxide at 300 K is cv,CO.

Conclusion:

Substitute Equation (II) and (III) in (I).

km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO

Thus, the specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Answer 7

Chapter 12.9, Problem 1E

To determine

The specific heat ratio using molar analysis.

Answer 8

Expert Solution & Answer

Answer to Problem 1E

The specific heat ratio using molar analysis is km=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,COmfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Write the expression to calculate the specific heat ratio of mixture km contains H2,O2 and CO using the following relation from molar analysis.

km=(cp)m(cv)m (I)

Here, the specific heat at constant pressure of the mixture is (cp)m, the specific heat at constant volume of the mixture is (cv)m.

Write the expression for specific heat at constant pressure of the mixture (cp)m.

(cp)m=mfH2⋅cp,H2+mfO2⋅cp,O2+mfCO⋅cp,CO (II)

Here, the mass fraction of hydrogen is mfH2, the mass fraction of oxygen is mfO2, the mass fraction of carbon monoxide is mfCO, the specific heat capacity at constant pressure of hydrogen at 300 K is cp,H2, the specific heat capacity at constant pressure of oxygen at 300 K is cp,O2, and the specific heat capacity at constant pressure of carbon monoxide at 300 K is cp,CO.

Write the expression for specific heat at constant volume of the mixture (cv)m.

(cv)m=mfH2⋅cv,H2+mfO2⋅cv,O2+mfCO⋅cv,CO (III)

Here, the specific heat capacity at constant volume of hydrogen at 300 K is cv,H2,the specific heat capacity at constant volume of oxygen at 300 K is cv,O2, specific heat capacity at constant volume of carbon monoxide at 300 K is cv,CO.