Explanation It is given that the hold time of callers to General Cable is normally distributed with a mean of 3.0 minutes and a standard deviation of 0.8 minute. Find the value of z for at least 4 minutes. z = 4 − mean standard deviation = 4 − 3.0 0.8 = 1 0.8 = 1.25 For z -scores greater than −3.49, use 1.000 to approximate the area. Use the Table 12.8 (b), the area to the left of z = 1.25 is 0.8944. Thus, the area between − 3.49 and 1.25 is, Area = ( z -scores greater than − 3

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Author: Christine D. Abbott, Allen R. Angel, Dennis Runde

Publisher: PEARSON

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 12.5, Problem 46E

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To find: How many are on hold for at least 4 minutes in a random sample of 500 callers.

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Chapter 12.5, Problem 45E

Chapter 12.5, Problem 47E

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How many are on hold for at least 4 minutes in a random sample of 500 callers.

Solution Summary: The author explains that 53 callers are on hold for at least 4 minutes in a random sample of 500 people.

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To find: How many are on hold for at least 4 minutes in a random sample of 500 callers.

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Chapter 12 Solutions