Explanation Approach: Shifting graph of equations If h and k are real numbers, then replacing x by x − h or by x + h and replacing y by y − k or by y + k . Calculation: Given that, the parabola has vertical axis of symmetry, so the equation has form, ( x − h ) 2 = 4 p ( y − k ) ... ( 1 ) Given that, the vertex is V ( 4 , − 1 ) , so h = 4 k = − 1 Given that, parabola that passes through the point ( 6 , − 2 ) , point x = 6 , and y = − 2 must be on parabola. Substitute 6 for x , − 2 for y , 4 for h , and − 1 for k in equation ( 1 ) .

4th Edition

ISBN: 2818000007824

Author: Stewart

Publisher: CENGAGE L

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Chapter 12.4, Problem 46E

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The equation of a shifted conic for parabola that passes through the point (6,−2), with vertex V(4,−1) and vertical axis of symmetry.

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Chapter 12.4, Problem 45E

Chapter 12.4, Problem 47E

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Chapter 12 Solutions

ALGEBRA AND TRIGONOMETRY-WEBASSIGN

Ch. 12.1 - A parabola is the set of all points in the plane...Ch. 12.1 - Prob. 2E Ch. 12.1 - Prob. 3E Ch. 12.1 - Prob. 4E Ch. 12.1 - Prob. 5E Ch. 12.1 - Prob. 6E Ch. 12.1 - 5-10 Graphs of Parabolas Match the equation with...Ch. 12.1 - Prob. 8E Ch. 12.1 - 5-10 Graphs of Parabolas Match the equation with...Ch. 12.1 - Prob. 10E

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The equation of a shifted conic for parabola that passes through the point ( 6 , − 2 ) , with vertex V ( 4 , − 1 ) and vertical axis of symmetry.

Solution Summary: The author explains the equation of a shifted conic for parabola that passes through the point (6,-2), with vertex V

To find:

The equation of a shifted conic for parabola that passes through the point (6,−2), with vertex V(4,−1) and vertical axis of symmetry.

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Chapter 12 Solutions

The equation of a shifted conic for parabola that passes through the point ( 6 , − 2 ) , with vertex V ( 4 , − 1 ) and vertical axis of symmetry.

Solution Summary: The author explains the equation of a shifted conic for parabola that passes through the point (6,-2), with vertex V

To find: The equation of a shifted conic for parabola that passes through the point (6,−2), with vertex V(4,−1) and vertical axis of symmetry.

Want to see the full answer?

Chapter 12 Solutions

To find:

The equation of a shifted conic for parabola that passes through the point (6,−2), with vertex V(4,−1) and vertical axis of symmetry.