Analysis from given section: For variable instance “ptr”: For main thread: From the given code, the variable “ptr” is a global variable. It is written by the main thread. For peer thread 0 and thread 1: The variable “ptr” is read by the peer threads. For variable instance “cnt”: For main thread: From the given code, the variable “cnt” is a static variable and it is contains with only one instance in memory. Hence, it is not exist in the main thread. For peer thread 0 and thread 1: The variable “cnt” is read and written by the peer threads. For variable instance “i.m”: For main thread: From the given code, the variable “i.m” is a local automatic variable. It is stored on the stack of the main thread. Hence, this variable is exist in the main thread. For peer thread 0 and thread 1: The given variable is stored on the main thread, while its corresponding value is passed to the peer threads, the peer threads never place it on the stack. So, it is not shared. For variable instance “msgs.m”: For main thread: From the given code, the variable “msgs.m” is a local automatic variable. It is stored on the stack of the main thread. Hence, it is exist in the main thread. For peer thread 0 and thread 1: The given variable is stored on the main thread...

Question

Want to see the full answer?

Answer 1

Expert Solution & Answer

Chapter 12.4, Problem 12.6PP

A.

Explanation of Solution

Analysis from given section:

For variable instance “ptr”:

For main thread:

From the given code, the variable “ptr” is a global variable.

It is written by the main thread.

For peer thread 0 and thread 1:

The variable “ptr” is read by the peer threads.

For variable instance “cnt”:

For main thread:

From the given code, the variable “cnt” is a static variable and it is contains with only one instance in memory. Hence, it is not exist in the main thread.

For peer thread 0 and thread 1:

The variable “cnt” is read and written by the peer threads.

For variable instance “i.m”:

For main thread:

From the given code, the variable “i.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, this variable is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread, while its corresponding value is passed to the peer threads, the peer threads never place it on the stack. So, it is not shared.

For variable instance “msgs.m”:

For main thread:

From the given code, the variable “msgs.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, it is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread...

B.

Explanation of Solution

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Design and draw a high-level "as-is" process diagram that illustrates a current process related to a product or service offered through the SSDCI.gov database.

Compare last-mile connections for connecting homes and businesses to the Internet

Explain wireless networking standards

Answer 2

Expert Solution & Answer

Chapter 12.4, Problem 12.6PP

A.

Explanation of Solution

Analysis from given section:

For variable instance “ptr”:

For main thread:

From the given code, the variable “ptr” is a global variable.

It is written by the main thread.

For peer thread 0 and thread 1:

The variable “ptr” is read by the peer threads.

For variable instance “cnt”:

For main thread:

From the given code, the variable “cnt” is a static variable and it is contains with only one instance in memory. Hence, it is not exist in the main thread.

For peer thread 0 and thread 1:

The variable “cnt” is read and written by the peer threads.

For variable instance “i.m”:

For main thread:

From the given code, the variable “i.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, this variable is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread, while its corresponding value is passed to the peer threads, the peer threads never place it on the stack. So, it is not shared.

For variable instance “msgs.m”:

For main thread:

From the given code, the variable “msgs.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, it is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread...

B.

Explanation of Solution

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 12.4, Problem 12.6PP

A.

Explanation of Solution

Analysis from given section:

For variable instance “ptr”:

For main thread:

From the given code, the variable “ptr” is a global variable.

It is written by the main thread.

For peer thread 0 and thread 1:

The variable “ptr” is read by the peer threads.

For variable instance “cnt”:

For main thread:

From the given code, the variable “cnt” is a static variable and it is contains with only one instance in memory. Hence, it is not exist in the main thread.

For peer thread 0 and thread 1:

The variable “cnt” is read and written by the peer threads.

For variable instance “i.m”:

For main thread:

From the given code, the variable “i.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, this variable is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread, while its corresponding value is passed to the peer threads, the peer threads never place it on the stack. So, it is not shared.

For variable instance “msgs.m”:

For main thread:

From the given code, the variable “msgs.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, it is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread...

B.

Explanation of Solution

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 12.4, Problem 12.6PP

A.

Explanation of Solution

Analysis from given section:

For variable instance “ptr”:

For main thread:

From the given code, the variable “ptr” is a global variable.

It is written by the main thread.

For peer thread 0 and thread 1:

The variable “ptr” is read by the peer threads.

For variable instance “cnt”:

For main thread:

From the given code, the variable “cnt” is a static variable and it is contains with only one instance in memory. Hence, it is not exist in the main thread.

For peer thread 0 and thread 1:

The variable “cnt” is read and written by the peer threads.

For variable instance “i.m”:

For main thread:

From the given code, the variable “i.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, this variable is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread, while its corresponding value is passed to the peer threads, the peer threads never place it on the stack. So, it is not shared.

For variable instance “msgs.m”:

For main thread:

From the given code, the variable “msgs.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, it is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread...

B.

Explanation of Solution

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 12.4, Problem 12.6PP

A.

Explanation of Solution

Analysis from given section:

For variable instance “ptr”:

For main thread:

From the given code, the variable “ptr” is a global variable.

It is written by the main thread.

For peer thread 0 and thread 1:

The variable “ptr” is read by the peer threads.

For variable instance “cnt”:

For main thread:

From the given code, the variable “cnt” is a static variable and it is contains with only one instance in memory. Hence, it is not exist in the main thread.

For peer thread 0 and thread 1:

The variable “cnt” is read and written by the peer threads.

For variable instance “i.m”:

For main thread:

From the given code, the variable “i.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, this variable is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread, while its corresponding value is passed to the peer threads, the peer threads never place it on the stack. So, it is not shared.

For variable instance “msgs.m”:

For main thread:

From the given code, the variable “msgs.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, it is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread...

B.

Explanation of Solution

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...

Answer 8

Chapter 12.4, Problem 12.6PP

A.

Explanation of Solution

Analysis from given section:

For variable instance “ptr”:

For main thread:

From the given code, the variable “ptr” is a global variable.

It is written by the main thread.

For peer thread 0 and thread 1:

The variable “ptr” is read by the peer threads.

For variable instance “cnt”:

For main thread:

From the given code, the variable “cnt” is a static variable and it is contains with only one instance in memory. Hence, it is not exist in the main thread.

For peer thread 0 and thread 1:

The variable “cnt” is read and written by the peer threads.

For variable instance “i.m”:

For main thread:

From the given code, the variable “i.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, this variable is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread, while its corresponding value is passed to the peer threads, the peer threads never place it on the stack. So, it is not shared.

For variable instance “msgs.m”:

For main thread:

From the given code, the variable “msgs.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, it is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread...

Answer 9

Chapter 12.4, Problem 12.6PP

A.

Explanation of Solution

Analysis from given section:

For variable instance “ptr”:

For main thread:

From the given code, the variable “ptr” is a global variable.

It is written by the main thread.

For peer thread 0 and thread 1:

The variable “ptr” is read by the peer threads.

For variable instance “cnt”:

For main thread:

From the given code, the variable “cnt” is a static variable and it is contains with only one instance in memory. Hence, it is not exist in the main thread.

For peer thread 0 and thread 1:

The variable “cnt” is read and written by the peer threads.

For variable instance “i.m”:

For main thread:

From the given code, the variable “i.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, this variable is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread, while its corresponding value is passed to the peer threads, the peer threads never place it on the stack. So, it is not shared.

For variable instance “msgs.m”:

For main thread:

From the given code, the variable “msgs.m” is a local automatic variable.

It is stored on the stack of the main thread. Hence, it is exist in the main thread.

For peer thread 0 and thread 1:

The given variable is stored on the main thread...

Answer 10

B.

Explanation of Solution

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...

Answer 11

B.

Explanation of Solution

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 12.1 - Prob. 12.1PP Ch. 12.1 - Prob. 12.2PP Ch. 12.2 - Practice Problem 12.3 (solution page 1036) In...Ch. 12.2 - Practice Problem 12.4 (solution page 1036) In the...Ch. 12.4 - Prob. 12.5PP Ch. 12.4 - Prob. 12.6PP Ch. 12.5 - Prob. 12.7PP Ch. 12.5 - Prob. 12.8PP Ch. 12.5 - Prob. 12.9PP Ch. 12.5 - Prob. 12.10PP

Solution Summary: The author explains that variable instance "ptr" is a global variable and is written by the main thread.

Explanation of Solution

Explanation of Solution

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...

Want to see the full answer?

Chapter 12 Solutions

Solution Summary: The author explains that variable instance "ptr" is a global variable and is written by the main thread.

Explanation of Solution

Explanation of Solution

Analysis of shared variable from part A: From the part A, the variables “ptr”,...

Want to see the full answer?

Chapter 12 Solutions

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...