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(a)
Interpretation:
The reagent for the given transformation should be identified.
Concept introduction:
The
The
9-BBN (9-Borabicyclo [3.3.1] nonane) or diborane is used for the hydroboration of
The role of dilute sulfuric acid is used for the hydration of alkene in
Reduction:
The oxymercuration reaction is an electrophilic addition reaction, an alkene undergoes oxymercuration and forms neutral alcohol.
Anti-Markovnikov’s rule: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the less substitution position of carbon-carbon double bond which provides
Markovnikov addition: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the more substitution position of carbon-carbon double bond which provides alkyl halides.
(b)
Interpretation:
The reagent for the given transformation should be identified.
Concept introduction:
The
The
9-BBN (9-Borabicyclo [3.3.1] nonane) or diborane is used for the hydroboration of alkene. Boron addition to the double bond and subsequent oxidation of the new formed borane yields anti-Markovnikov alcohols.
The role of dilute sulfuric acid is used for the hydration of alkene in organic synthesis.
Reduction: Aldehydes or ketones undergoing reduction by using reducing agent like LAH or NaBH4 which provides alcohol.
The oxymercuration reaction is an electrophilic addition reaction, an alkene undergoes oxymercuration and forms neutral alcohol.
Anti-Markovnikov’s rule: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.
Markovnikov addition: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the more substitution position of carbon-carbon double bond which provides alkyl halides.
(c)
Interpretation:
The reagent for the given transformation should be identified.
Concept introduction:
The
The
9-BBN (9-Borabicyclo [3.3.1] nonane) or diborane is used for the hydroboration of alkene. Boron addition to the double bond and subsequent oxidation of the new formed borane yields anti-Markovnikov alcohols.
The role of dilute sulfuric acid is used for the hydration of alkene in organic synthesis.
Reduction: Aldehydes or ketones undergoing reduction by using reducing agent like LAH or NaBH4 which provides alcohol.
The oxymercuration reaction is an electrophilic addition reaction, an alkene undergoes oxymercuration and forms neutral alcohol.
Anti-Markovnikov’s rule: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.
Markovnikov addition: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the more substitution position of carbon-carbon double bond which provides alkyl halides.
(d)
Interpretation:
The reagent for the given transformation should be identified.
Concept introduction:
The
The
9-BBN (9-Borabicyclo [3.3.1] nonane) or diborane is used for the hydroboration of alkene. Boron addition to the double bond and subsequent oxidation of the new formed borane yields anti-Markovnikov alcohols.
The role of dilute sulfuric acid is used for the hydration of alkene in organic synthesis.
Reduction: Aldehydes or ketones undergoing reduction by using reducing agent like LAH or NaBH4 which provides alcohol.
The oxymercuration reaction is an electrophilic addition reaction, an alkene undergoes oxymercuration and forms neutral alcohol.
Anti-Markovnikov’s rule: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.
Markovnikov addition: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the more substitution position of carbon-carbon double bond which provides alkyl halides.
(e)
Interpretation:
The reagent for the given transformation should be identified.
Concept introduction:
The
The
9-BBN (9-Borabicyclo [3.3.1] nonane) or diborane is used for the hydroboration of alkene. Boron addition to the double bond and subsequent oxidation of the new formed borane yields anti-Markovnikov alcohols.
The role of dilute sulfuric acid is used for the hydration of alkene in organic synthesis.
Reduction: Aldehydes or ketones undergoing reduction by using reducing agent like LAH or NaBH4 which provides alcohol.
The oxymercuration reaction is an electrophilic addition reaction, an alkene undergoes oxymercuration and forms neutral alcohol.
Anti-Markovnikov’s rule: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.
Markovnikov addition: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the more substitution position of carbon-carbon double bond which provides alkyl halides.
(f)
Interpretation:
The reagent for the given transformation should be identified.
Concept introduction:
The
The
9-BBN (9-Borabicyclo [3.3.1] nonane) or diborane is used for the hydroboration of alkene. Boron addition to the double bond and subsequent oxidation of the new formed borane yields anti-Markovnikov alcohols.
The role of dilute sulfuric acid is used for the hydration of alkene in organic synthesis.
Reduction: Aldehydes or ketones undergoing reduction by using reducing agent like LAH or NaBH4 which provides alcohol.
The oxymercuration reaction is an electrophilic addition reaction, an alkene undergoes oxymercuration and forms neutral alcohol.
Anti-Markovnikov’s rule: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.
Markovnikov addition: unsymmetrical alkene reacts with hydrogen halide, halide ions (negative part) goes to the more substitution position of carbon-carbon double bond which provides alkyl halides.
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Chapter 12 Solutions
Organic Chemistry Third Edition + Electronic Solutions Manual And Study Guide
- Nonearrow_forwardQ1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? H Br H Br (S) CH3 (R) CH3 H3C (S) H3C H Br Br H A C enantiomers H Br H Br (R) CH3 H3C (R) (S) CH3 H3C H Br Br H B D identicalarrow_forward2. Histamine (below structure) is a signal molecule involved in immune response and is a neurotransmitter. Histamine features imidazole ring which is an aromatic heterocycle. Please answer the following questions regarding Histamine. b a HN =N C NH2 a. Determine hybridization of each N atom (s, p, sp, sp², sp³, etc.) in histamine N-a hybridization: N-b hybridization: N-c hybridization: b. Determine what atomic orbitals (s, p, sp, sp², sp³, etc.) of the lone pair of each N atom resided in N-a hybridization: N-b hybridization: N-c hybridization:arrow_forward
- Nonearrow_forward29. Use frontier orbital analysis (HOMO-LUMO interactions) to decide whether the following dimerization is 1) thermally allowed or forbidden and 2) photochemically allowed or forbidden. +arrow_forward30.0 mL of 0.10 mol/L iron sulfate and 20.0 mL of 0.05 mol/L of silver nitrate solutions are mixed together. Justify if any precipitate would formarrow_forward
- Does the carbonyl group first react with the ethylene glycol, in an intermolecular reaction, or with the end alcohol, in an intramolecular reaction, to form a hemiacetal? Why does it react with the alcohol it does first rather than the other one? Please do not use an AI answer.arrow_forwardThe number of noncyclic isomers that have the composition C4H8Owith the O as part of an OH group, counting a pair of stereoisomers as1, is A. 8; B. 6; C. 9; D. 5; E. None of the other answers is correct.arrow_forwardNonearrow_forward
- The number of carbon skeletons that have 8 carbons, one of which istertiary is A. 7; B. More than 7; C. 6; D. 5; E. 4arrow_forwardThe azide ion is N3^-. In addition to the ionic charge, it’s three mostimportant contributing structures also have formal charges. The totalnumber of π bonds in these three contributing structures isA. 6; B. 12; C. 3; D. 9; E. None of the other answers is correct.arrow_forwardThe sum of the numerals in the name of the compoundis A. None of the other answers is correct.; B. 11;C. 6; D. 8; E. 5.arrow_forward
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