EP ORGANIC CHEMISTRY,24 MONTH-OWLV2
9th Edition
ISBN: 9781305084391
Author: McMurry
Publisher: CENGAGE L
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Chapter 12.3, Problem 4P
Interpretation Introduction
Interpretation:
The masses of the parent ion and several other fragments formed, expected to be found in the mass spectrum of the compound represented by the model, are to be given.
Concept introduction:
Alcohols undergo fragmentation by both dehydration and alpha cleavage. In the alpha cleavage a C-C bond is broken to yield a neutral radical along with a resonance stabilized oxygen containing cation.
To give:
The masses of the parent ion and several other fragments formed, expected to be found in the mass spectrum of the compound represented by the model.
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Solve for x, where M is molar and s is seconds.
x = (9.0 × 10³ M−². s¯¹) (0.26 M)³
Enter the answer. Include units. Use the exponent key above the answer box to indicate any exponent on your units.
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 12 Solutions
EP ORGANIC CHEMISTRY,24 MONTH-OWLV2
Ch. 12.2 - Prob. 1PCh. 12.2 - Two mass spectra are shown in FIGURE 12-8. One...Ch. 12.3 - What are the masses of the charged fragments...Ch. 12.3 - Prob. 4PCh. 12.5 - Prob. 5PCh. 12.5 - Prob. 6PCh. 12.7 - What functional groups might the following...Ch. 12.7 - How might you use IR spectroscopy to distinguish...Ch. 12.8 - Prob. 9PCh. 12.8 - Where might the following compounds have IR...
Ch. 12.8 - Where might the following compound have IR...Ch. 12.SE - Prob. 12VCCh. 12.SE - Show the structures of the fragments you would...Ch. 12.SE - Propose structures for compounds that fit the...Ch. 12.SE - Write molecular formulas for compounds that show...Ch. 12.SE - Camphor, a saturated monoketone from the Asian...Ch. 12.SE - The nitrogen rule of mass spectrometry says that a...Ch. 12.SE - In light of the nitrogen rule mentioned in Problem...Ch. 12.SE - Nicotine is a diamino compound isolated from dried...Ch. 12.SE - The hormone cortisone contains C, H, and O, and...Ch. 12.SE - Halogenated compounds are particularly easy to...Ch. 12.SE - Prob. 22APCh. 12.SE - Propose structures for compounds that fit the...Ch. 12.SE - 2-Methylpentane (C6H14) has the mass spectrum...Ch. 12.SE - Assume that you are in a laboratory carrying out...Ch. 12.SE - What fragments might you expect in the mass...Ch. 12.SE - How might you use IR spectroscopy to distinguish...Ch. 12.SE - Would you expect two enantiomers such as...Ch. 12.SE - Would you expect two diastereomers such as meso-2,...Ch. 12.SE - Propose structures for compounds that meet the...Ch. 12.SE - How could you use infrared spectroscopy to...Ch. 12.SE - Prob. 32APCh. 12.SE - At what approximate positions might the following...Ch. 12.SE - How would you use infrared spectroscopy to...Ch. 12.SE - At what approximate positions might the following...Ch. 12.SE - Assume that you are carrying out the dehydration...Ch. 12.SE - Assume that you are carrying out the base-induced...Ch. 12.SE - Prob. 38APCh. 12.SE - Carvone is an unsaturated ketone responsible for...Ch. 12.SE - Prob. 40APCh. 12.SE - The mass spectrum (a) and the infrared spectrum...Ch. 12.SE - The mass spectrum (a) and the infrared spectrum...Ch. 12.SE - Propose structures for compounds that meet the...Ch. 12.SE - 4-Methyl-2-pentanone and 3-methylpentanal are...Ch. 12.SE - Grignard reagents undergo a general and very...Ch. 12.SE - Ketones undergo a reduction when treated with...Ch. 12.SE - Nitriles, R–=C≡N, undergo a hydrolysis...Ch. 12.SE - The infrared spectrum of the compound with the...Ch. 12.SE - The infrared spectrum of the compound with the...Ch. 12.SE - Prob. 50AP
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- need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…arrow_forwardPlease correct answer and don't used hand raitingarrow_forwardneed help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forward
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