Explanation Proof: If two states of a particular finite-state automaton are ∗ − equivalent, we can observe that applying a string of inputs to these two states brings the automaton to an accepting state or nonaccepting state. Here we obtain two equivalent classes only

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Chapter 12.3, Problem 18ES

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To prove:

That any ∗− equivalent class cannot have both accepting and nonaccepting states.

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Chapter 12.3, Problem 17ES

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To prove: That any ∗ − equivalent class cannot have both accepting and nonaccepting states.

Solution Summary: The author proves that any ast - equivalent class cannot have both accepting and nonaccepting states.

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To prove:

That any ∗− equivalent class cannot have both accepting and nonaccepting states.

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Chapter 12 Solutions

To prove: That any ∗ − equivalent class cannot have both accepting and nonaccepting states.

Solution Summary: The author proves that any ast - equivalent class cannot have both accepting and nonaccepting states.

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To prove: That any ∗− equivalent class cannot have both accepting and nonaccepting states.

Want to see the full answer?

Chapter 12 Solutions

To prove:

That any ∗− equivalent class cannot have both accepting and nonaccepting states.