Chapter 12.2, Problem 62E

To determine

For the function $f\left(x\right)=0.55x^3-20.3x^2+249x-1000$; $10\le x\le 16$ here $x=10$ corresponds to the year 2010.

The first derivative of $f\left(x\right)=0.55x^3-20.3x^2+249x-1000$.

The critical numbers of $f\left(x\right)=0.55x^3-20.3x^2+249x-1000$.

The second derivative of $f\left(x\right)=0.55x^3-20.3x^2+249x-1000$.

The local minimum and maximum of $f\left(x\right)=0.55x^3-20.3x^2+249x-1000$.